Reputation: 1659
When using Objective-C I would pass a NSMutableArray
from one view controller VC_A
to another VC_B
by simply assigning a property in VC_B
as
VC_B.list = self.list
where self is VC_A
It allows the changes done in VC_B
on the list to be seen in the list in VC_A
when the view controller was say popped off the navigation stack.
However in Swift as arrays are passed by value, assigning as above does not work so I am stuck how to solve this. What would be the correct way to handle this now?
Upvotes: 2
Views: 2515
Reputation: 299345
You can still do this in Swift by making the property an NSMutableArray
, just as before. Foundation types still exist if you ask for them. But this is bad design in both ObjC and Swift. It creates spooky action at a distance (when things magically change values that were not part of the call) and likely breaks MVC (if the data is persistent, it should live in the model, not in the view controllers).
There are two common patterns in Cocoa: store the data in the model, or pass it via delegation.
If this array represents some kind of persistent state (such as a list of items in the system), then that belongs in the model layer, and both view controllers should read and manipulate it there rather than by communicating with each other. (See Model-View-Controller.)
If this array is a transient piece of data (such as selections from a list), then the calling VC should set itself as the delegate to the receiving VC, and when the receiving VC finishes, it should pass the data back to its delegate. (See Delegates and Data Sources.)
Upvotes: 3
Reputation: 13243
If you use the standard Swift Array
which is a value type you have to use a wrapper or a untyped NSArray
.
// a generic wrapper class
class Reference<T> {
var value: T
init(_ val: T) { value = val }
}
// Usage
class ViewController1 {
static var list = Reference<[Int]>([])
}
class ViewController2 {
static var list = Reference([3, 5, 7, 9, 11])
func passToOtherVC() {
ViewController1.list = self.list
}
}
If you want to mutate the array you should always change the value
property of the Reference
object.
Upvotes: 2
Reputation: 6703
Just as a potential proof of concept that complements my comment on the question - it is possible to use the Objective-C NSMutableArray to accomplish this task:
class A {
var x: NSMutableArray = NSMutableArray(capacity: 12)
}
class B {
var y: NSMutableArray!
}
let a = A()
let b = B()
b.y = a.x
b.y[0] = 123
assert(a.x[0] === b.y[0])
Still, this is approach is not following the Swift style of handling data structures IMO.
Upvotes: -1
Reputation: 2854
In Swift, objects are automatically passed by reference. NSArray is an Objective C class (pass by reference), where as Array is a struct (pass by value).
So if you are working with NSMutableArray the array is already being passed by reference.
Upvotes: 1