CODEWITHSUNDEEP
phpstring
AEA
AEA

Reputation: 23

Get image name from path

I´m searching solution for this:

I have a paths:

$PATH = images/large/Wildebeest-01.jpg
$PATH = images/large/greater-kudu-02.jpg
$PATH = images/large/BLUE-AND-YELLOW-MACAW-08.jpg

Which I need is this:

"Wildebeest"
"Greater kudu"
"Blue and yellow macaw"

i have a first part of the solution:

$PATH = $image;
$file = substr(strrchr($PATH, "/"), 1); 
echo  $file;

which gives me:

Could someone advise me, how to remove at least "-01.jpg" from the string?

Thanks!

Upvotes: 1

Views: 1637

Answers (6)

AEA
AEA

Reputation: 23

Thanks guys! Based on your answers, I found the perfect solution:

$filename = pathinfo($PATH);
$filename = $filename['filename'];
$filename = preg_replace("/-[^-]*$/", "", $filename);
$filename= ucfirst(strtolower(str_replace('-',' ',$filename)));
echo $filename;

Upvotes: 0

Luis Martin
Luis Martin

Reputation: 973

Yet another solution, using preg_match().:

$getImageName = function ($path) {
   if (preg_match('/([\w\d-_]+)-\d+\.(jpg|jpeg|png|gif)$/i', $path, $matches)) {
       return ucwords(strtolower(str_replace(str_split('-_'), ' ', $matches[1])));
   }
   return false;
};

$paths = array(
   'images/large/Wildebeest-01.jpg',
   'images/large/greater-kudu-02.jpg',
   'images/large/BLUE-AND-YELLOW-MACAW-08.jpg',
);

$names = array_map($getImageName, $paths);


print_r($names);

Result:

Array
(
    [0] => Wildebeest
    [1] => Greater Kudu
    [2] => Blue And Yellow Macaw
)

Upvotes: 0

hellcode
hellcode

Reputation: 2698

My suggestion:

$array = array();
$array[] = "images/large/Wildebeest-01.jpg";
$array[] = "images/large/greater-kudu-02.jpg";
$array[] = "images/large/BLUE-AND-YELLOW-MACAW-08.jpg";

function get_image_name($path) {
    $file = basename($path);
    if(preg_match("/(.*?)(-[0-9]*){0,1}([.][a-z]{3})/",$file,$reg)) {
        $file = $reg[1];
    }
    $file = ucfirst(strtolower(str_replace("-"," ",$file)));
    return $file;
}

foreach($array as $path) {
    echo "<br>".$path;
    echo " => ".get_image_name($path);
}

Output is:

images/large/Wildebeest-01.jpg => Wildebeest
images/large/greater-kudu-02.jpg => Greater kudu
images/large/BLUE-AND-YELLOW-MACAW-08.jpg => Blue and yellow macaw

Upvotes: 0

Vishwa
Vishwa

Reputation: 1545

Continuing with your solution..

$PATH = $image;
$file = substr(strrchr($PATH, "/"), 1); 

$op = preg_replace("/([a-zA-Z-]+).*/", "$1", $file);
$filename = trim( str_replace('-', '', $op); 
echo $filename; // outputs Wildebeest

Upvotes: 0

Hurricane Development
Hurricane Development

Reputation: 2464

You have the right idea for getting the file

$file = substr($PATH,strrpos($PATH, "/"));

Then to get rid of everything after the last - simply do.

$file = substr($file,0,strrpos($file,'-'));

Then turn - into .

$file = str_replace('-',' ',$file);

EDIT

If you don't care about possible changes in the future, like bigger numbers, different file extensions, and more. You can simply do.

$file = substr($file,0,-5);

Upvotes: 0

CodeGodie
CodeGodie

Reputation: 12132

Try this, it uses preg_replace:

$arr = ["Wildebeest-01.jpg", "greater-kudu-02.jpg", "BLUE-AND-YELLOW-MACAW-08.jpg"];
foreach ($arr as $string) {
    $string = preg_replace("/-[^-]*$/", "", $string);
    $string = str_replace("-", " ", $string);
    $string = strtolower($string);
    var_dump($string);
}

Upvotes: 1

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