CODEWITHSUNDEEP
pythondjangodjango-models
Parmis Moghadamian
Parmis Moghadamian

Reputation: 67

NameError in Django models.py

I have 5 classes, Customer, Supplier, Order, Design and OutSource. The Order has 3 relationships, one to one with Customer, many to many with Designand one to one with OutSourse. first I just did add its one to one relationship withCustomer(customer=models.ForeignKey(Customer)), now I wanna add the those 2 relationships withDesignandOutsourse`.

 design=models.ManyToManyField(Design)
 outSource=models.OneToOneField(OutSource)

when I do that and run the "makemigrations" command I get this error--> "NameError:name "Design" is not defined" without those 2 lines of code I can migrate without any kinda problem...can't figure out where I'm going wrong. any help will be appreciated.

models.py

class Order(models.Model):
    o_type=models.CharField(max_length=15, verbose_name='Order type')
    number=models.IntegerField()
    date=models.DateField()
    status=models.CharField(max_length=25)
    delivery_date=models.DateField()
    customer=models.ForeignKey(Customer)
    design=models.ManyToManyField(Design)
    outSource=models.OneToOneField(OutSource)

class Design(models.Model):
    dimension=models.IntegerField()
    image=models.ImageField(upload_to='images/%Y/%m/%d')
    number_of_colors=models.IntegerField()
    sides=models.IntegerField(verbose_name='side(s)')

class OutSource(models.Model):
    date=models.DateField()
    number=models.IntegerField()
    description=models.CharField(max_length=100)
    code=models.IntegerField()
    supplier=models.ForeignKey(Supplier)

Upvotes: 1

Views: 902

Answers (1)

Arpit Goyal
Arpit Goyal

Reputation: 2254

You are declaring the class Design after actually defining the ManyToManyField relationship. It cannot find the class with name Design and hence the NameError.

Declare the class Design before class Order and things should work for you.

Upvotes: 5

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