Reputation: 4331
I have a random integer value which I need to represent in String as a Byte array. For example:
int value = 32;
String strValue = getStringByteArray(value);
Console.WriteLine(strValue); // should write: " \0\0\0"
If value = 11
then getStringByteArray(value)
shuld return "\v\0\0\0"
.
If value = 13
then getStringByteArray(value)
shuld return "\r\0\0\0"
.
And so on.
Any idea on how to implement the method getStringByteArray(int value)
in C#?
UPDATE
This is the code that receives the data from the C# NamedPipe Server:
bool CFilePipe::ReadString(int m_handle, string &value)
{
//--- check for data
if(WaitForRead(sizeof(int)))
{
ResetLastError();
int size=FileReadInteger(m_handle);
if(GetLastError()==0)
{
//--- check for data
if(WaitForRead(size))
{
value=FileReadString(m_handle,size);
return(size==StringLen(value));
}
}
}
//--- failure
return(false);
}
Upvotes: 1
Views: 4170
Reputation: 1502036
Don't take this approach at all. You should be writing to a binary stream of some description - and write the binary data for the length of the packet/message, followed by the message itself. For example:
BinaryWriter writer = new BinaryWriter(stream);
byte[] data = Encoding.UTF8.GetBytes(text);
writer.Write(data.Length);
writer.Write(data);
Then at the other end, you'd use:
BinaryReader reader = new BinaryReader(stream);
int length = reader.ReadInt32();
byte[] data = reader.ReadBytes(length);
string text = Encoding.UTF8.GetString(data);
No need to treat binary data as text at all.
Upvotes: 8
Reputation: 2296
Well. First of all you should get bytes from integer. You can do it with BitConverter:
var bytes = BitConverter.GetBytes(value);
Next, here is three variants. First - if you want to get result in binary format. Just take all your bytes and write as it is:
var str = string.Concat(bytes.Select(b => Convert.ToString(b, 2)));
Second variant. If you want convert your byte array to hexadecimal string:
var hex = BitConverter.ToString(array).Replace("-","");
Third variant. Your representation ("\v\0\0\0") - it is simple converting byte to char. Use this:
var s = bytes.Aggregate(string.Empty, (current, t) => current + Convert.ToChar(t));
Upvotes: 2
Reputation: 1061
I think you are saying that you want to convert each byte into a character literal, using escape sequences for the non printable characters.
After converting the integer to 4 bytes, cast to char. Then use Char.IsControl() to identify the non-printing characters. Use the printable char directly, and use a lookup table to find the corresponding escape sequence for each non-printable char.
Upvotes: 1
Reputation: 507
Obviously, you should implement two steps to achieve the goal:
Extract bytes from the integer in the appropriate order (little-endian or big-endian, it's up to you to decide), using bit arithmetics.
Merge extracted bytes into string using the format you need.
Possible implementation:
using System;
using System.Text;
public class Test
{
public static void Main()
{
Int32 value = 5152;
byte[] bytes = new byte[4];
for (int i = 0; i < 4; i++)
{
bytes[i] = (byte)((value >> i * 8) & 0xFF);
}
StringBuilder result = new StringBuilder();
for (int i = 0; i < 4; i++)
{
result.Append("\\" + bytes[i].ToString("X2"));
}
Console.WriteLine(result);
}
}
Ideone snippet: http://ideone.com/wLloo1
Upvotes: 1
Reputation: 386
This should help with that.
class Program
{
static void Main(string[] args)
{
Random rand = new Random();
int number = rand.Next(1, 1000);
byte[] intBytes = BitConverter.GetBytes(number);
string answer = "";
for (int i = 0; i < intBytes.Length; i++)
{
answer += intBytes[i] + @"\";
}
Console.WriteLine(answer);
Console.WriteLine(number);
Console.ReadKey();
}
}
Upvotes: 1