CODEWITHSUNDEEP
javaandroidjsongson
Alexandr
Alexandr

Reputation: 1901

Custom parse JSON fields with GSON

I have following json:

{
    "id": 1,
    "title": "Title blabla",
    "thing": {
        "field1": 1,
        "field2": "field2",
        "etc": "etc.."
    }
}

and model 

public class MyModel {
    private int id;
    private String title;
    private String thing;
}

I parse it with gson 

 Gson gson = new Gson();
 MyModel myModel = gson.fromJson(json, type);

and want achieve result:

myModel.id -> 1
myModel.title -> "Title blabla"
myModel.thing-> "{
              "field1": 1,
              "field2": "field2",
              "etc": "etc.."
             }"

In other words I do not want some fields to be deserialized, but left as the original coresponding json strings.

How to achieve this using gson?

Upvotes: 1

Views: 565

Answers (4)

Leonid Glanz
Leonid Glanz

Reputation: 1261

You could change String to Object so that it de-/serializes to the same JSON String. Could look like that:

import com.google.gson.Gson;

public class Answers {
    public static void main(String[] args) {
        String json = "{" 
                + "    \"id\": 1,"
                + "    \"title\": \"Title blabla\"," + "    \"thing\": {"
                + "        \"field1\": 1," + "        \"field2\": \"field2\","
                + "        \"etc\": \"etc..\"" + "    }" 
                + "}";
        Gson gson = new Gson();
        MyModel myModel = (MyModel) gson.fromJson(json, MyModel.class);
        System.out.println(gson.toJson(myModel));

    }

    class MyModel {
        private int id;
        private String title;
        private Object thing;
    }

}

Output:

{"id":1,"title":"Title blabla","thing":{"field1":1.0,"field2":"field2","etc":"etc.."}}

Upvotes: 1

Ofek Ron
Ofek Ron

Reputation: 8580

You can implement your own serializer and desirializer, see here for example.

Upvotes: 2

Thom
Thom

Reputation: 15052

You could change thing to a Map and then toString() that to produce the results you're looking for.

Upvotes: 2

Ahmed Abidi
Ahmed Abidi

Reputation: 1077

You have to use an inner class if you want to parse a similar JSON object, try this for example :

public class MyModel {
    private int id;
    private String title;
    private String thing;
     public static class thing
     {
     private string field1;
     private string field2;
     etc etc
     }
}

Upvotes: 1

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