CODEWITHSUNDEEP
javaregex
paul
paul

Reputation: 13471

Regex not filter by delimiters

I want to create a regular expresion where I want match in case my number are separated by a coma. For example:

 1 OK
 1,2,3 OK
 1\n2,3 OK
 1,\n Not OK
 1,,2 Not OK
 1,\n2 Not Ok

So far I create this expresion

 \d+(([,.|\n])+\d+)*

If I change the last * to be at least 1 with +

 \d+(([,.|\n])+\d+)+

Then all previous scenarios works but not this one

  1 Not OK//And should be ok

I´m using matcher.find() 

    Matcher matcher = Pattern.compile(pattern).matcher(number);
    if (matcher.find()) {
        System.out.println("total number:" + matcher.group(0));;
    }

Any idea what I´m doing wrong in my regex?

Upvotes: 1

Views: 56

Answers (1)

anubhava
anubhava

Reputation: 785631

You can use this regex:

^\d+(?:(?:,|\n)\d+)*$

Java regex:

Pattern p = Pattern.compile("^\\d+(?:(?:,|\\n)\\d+)*$");

RegEx Demo

PS: To match literal \n you will need:

^\d+(?:(?:,|\\n)\d+)*$

Upvotes: 1

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