CODEWITHSUNDEEP
javascriptalgorithmfunctionmatheasing
Dan
Dan

Reputation: 1559

Reversing easing function

I have the following function:

Math.easeIn = function (val, min, max) {
  strength = 4;
  val /= max;
  return (max-1)*Math.pow(val, strength) + min;
};

Given Math.easeIn(5, 1, 10), I get 1.5625. I would like a function that given a val of 1.5625, it returns 5.

I.e. Math.easeOut(1.5625, 1, 10) -> 5

My math skills are letting me down here.

Upvotes: 1

Views: 535

Answers (1)

blex
blex

Reputation: 25659

Math.easeIn = function (val, min, max) {
  strength = 4;
  val /= max;
  return (max-1)*Math.pow(val, strength) + min;
};

Math.easeOut = function (val, min, max) {
  var strength = 4, res;
  res = (val-min)/(max-1);
  res = Math.pow(res, 1/strength);
  return max*res;
};

document.body.innerHTML = '<p>easeIn : ' + Math.easeIn(5, 1, 10) + '</p>';

document.body.innerHTML += '<p>easeOut : ' + Math.easeOut(1.5625, 1, 10) + '</p>';

I obtained this by reversing your easeIn function:

res = (max - 1) * Math.pow(val/max, strength) + min     // Your easeIn function
res - min = (max - 1) * Math.pow(val/max, strength)
(res - min)/(max - 1) = Math.pow(val/max, strength)
Math.pow( (res - min)/(max - 1), 1/strength ) = val / max
Math.pow( (res - min)/(max - 1), 1/strength ) * max = val   // Your easeOut function

Upvotes: 3

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