CODEWITHSUNDEEP
javaregex
goe
goe

Reputation: 1243

How to split a big number using regex in java?

This is my number "1508261". In the end I want to have a List of ("15","08","261"). Meaning, the pattern should always create two new numbers with two digits in each and the remaining digits should be all included in the last (third) number.

I tried using this approach but it returns ("1508261"):

Pattern pattern = Pattern.compile("([0-9]{2})([0-9]{2})([0-9]{1,})");    
Matcher matcher = pattern.matcher("1508261");
    ArrayList<String> list = new ArrayList<String>();
    while (matcher.find()) {
       list.add(matcher.group());
    }

Upvotes: 0

Views: 170

Answers (1)

Mauren
Mauren

Reputation: 1975

Your snippet tests the whole pattern against the input string, not each group separately. You might want to use Matcher.matches() and Matcher.group(int) instead of Matcher.find():

    Pattern pattern = Pattern.compile("([0-9]{2})([0-9]{2})([0-9]{1,})");    
    Matcher matcher = pattern.matcher("1508261");
    ArrayList<String> list = new ArrayList<String>();
    if(matcher.matches()) {
        for(int i = 1;i <= matcher.groupCount();i++)
            list.add(matcher.group(i));
    }

    System.out.println(list);

Live example in Ideone here.

Also note that Matcher.group() and Matcher.group(0) do the same job. More info can be found in the Oracle Java Regex Tutorial.

Upvotes: 4

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