Reputation: 63984
With the following code:
import matplotlib
matplotlib.style.use('ggplot')
import matplotlib.pyplot as plt
import pandas as pd
df = pd.DataFrame({ 'celltype':["foo","bar","qux","woz"], 's1':[5,9,1,7], 's2':[12,90,13,87]})
df = df[["celltype","s1","s2"]]
df.set_index(["celltype"],inplace=True)
df.plot(kind='bar',alpha=0.75)
plt.xlabel("")
I made this plot:
How can I rotate the x-axis tick labels to 0 degrees?
I tried adding this but did not work:
plt.set_xticklabels(df.index,rotation=90)
Upvotes: 184
Views: 253741
Reputation: 393943
Pass param rot=0
to rotate the xticklabels:
import matplotlib
matplotlib.style.use('ggplot')
import matplotlib.pyplot as plt
import pandas as pd
df = pd.DataFrame({ 'celltype':["foo","bar","qux","woz"], 's1':[5,9,1,7], 's2':[12,90,13,87]})
df = df[["celltype","s1","s2"]]
df.set_index(["celltype"],inplace=True)
df.plot(kind='bar',alpha=0.75, rot=0)
plt.xlabel("")
plt.show()
yields plot:
Upvotes: 325
Reputation: 560
You can use set_xticklabels()
ax.set_xticklabels(df['Names'], rotation=90, ha='right')
Upvotes: 14
Reputation: 3318
The follows might be helpful:
# Valid font size are xx-small, x-small, small, medium, large, x-large, xx-large, larger, smaller, None
plt.xticks(
rotation=45,
horizontalalignment='right',
fontweight='light',
fontsize='medium',
)
Here is the function xticks
[reference] with example and API
def xticks(ticks=None, labels=None, **kwargs):
"""
Get or set the current tick locations and labels of the x-axis.
Call signatures::
locs, labels = xticks() # Get locations and labels
xticks(ticks, [labels], **kwargs) # Set locations and labels
Parameters
----------
ticks : array_like
A list of positions at which ticks should be placed. You can pass an
empty list to disable xticks.
labels : array_like, optional
A list of explicit labels to place at the given *locs*.
**kwargs
:class:`.Text` properties can be used to control the appearance of
the labels.
Returns
-------
locs
An array of label locations.
labels
A list of `.Text` objects.
Notes
-----
Calling this function with no arguments (e.g. ``xticks()``) is the pyplot
equivalent of calling `~.Axes.get_xticks` and `~.Axes.get_xticklabels` on
the current axes.
Calling this function with arguments is the pyplot equivalent of calling
`~.Axes.set_xticks` and `~.Axes.set_xticklabels` on the current axes.
Examples
--------
Get the current locations and labels:
>>> locs, labels = xticks()
Set label locations:
>>> xticks(np.arange(0, 1, step=0.2))
Set text labels:
>>> xticks(np.arange(5), ('Tom', 'Dick', 'Harry', 'Sally', 'Sue'))
Set text labels and properties:
>>> xticks(np.arange(12), calendar.month_name[1:13], rotation=20)
Disable xticks:
>>> xticks([])
"""
Upvotes: 6
Reputation: 4030
The question is clear but the title is not as precise as it could be. My answer is for those who came looking to change the axis label, as opposed to the tick labels, which is what the accepted answer is about. (The title has now been corrected).
for ax in plt.gcf().axes:
plt.sca(ax)
plt.xlabel(ax.get_xlabel(), rotation=90)
Upvotes: 9