guitar-
guitar-

Reputation: 1101

PHP - Calling .php file from command line produces no output

I have a simple cmd.php page to run commands I enter using shell_exec () and show the output.

I attached a couple of images to show what I mean.

PHP -v doesn't produce expected output

PHP -v doesn't produce expected output

PHP -z shows PHP's usage

PHP -z shows PHP's usage

Any ideas?

Edit

cmd.php

<?php

    if ( isset ( $_POST['submit'] ) ) :

        $response = shell_exec ( escapeshellcmd ( stripslashes ( $_POST['cmd'] ) ) );

    endif;

?><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
    <head>
        <style type="text/css">
            pre#response { border: 1px solid #e0e0e0; padding: .5em; }
        </style>
        <title>Command</title>
    </head>
    <body>
        <form action="cmd.php" method="post">
            <p><input type="text" name="cmd" id="cmd" value="<?php echo @htmlspecialchars ( stripslashes ( $_POST['cmd'] ) ); ?>" size="50" />
            <button type="submit" name="submit" id="submit" value="Submit">Submit</button>
            </p>
        </form>


        <?php
        if ( isset ( $response ) ) :
        ?>

            <pre id="response"><?php

                if ( empty ( $response ) ) :
                    echo 'No response.';
                else :
                    echo htmlspecialchars ( $response );
                endif;
            ?></pre>

        <?php
        endif;
        ?>

    </body>
</html>

Upvotes: 0

Views: 4044

Answers (2)

user1104456
user1104456

Reputation: 83

Please check php.ini used by php from command line. I had same problem (no output from php command line), tried replacing current php.ini with php.ini-production and command line php started to work fine. It appears that some configuration variables were modified in recent php version (upgraded from 5.3.10 to 5.4.3).

Upvotes: 0

VolkerK
VolkerK

Reputation: 96159

shell_exec() only returns the characters that have been written to the stdout of the executed process, but not stderr. Try redirecting stderr to stdout so that error messages will be stored in $response.

<?php
define('REDIRECT_STDERR', 1);

if ( isset ( $_POST['submit'] ) ) :      
  $cmd = escapeshellcmd ( stripslashes ($_POST['cmd']) );
  if ( defined('REDIRECT_STDERR') && REDIRECT_STDERR ) :
    $cmd .= ' 2>&1';
  endif;
  $response = shell_exec( $cmd );
endif;

?><!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01//EN" "http://www.w3.org/TR/html4/strict.dtd">
<html>
  <head>
    <style type="text/css">
      pre#response { border: 1px solid #e0e0e0; padding: .5em; }
    </style>
    <title>Command</title>
  </head>
  <body>
    <form action="cmd.php" method="post">
      <p>
        <input type="text" name="cmd" id="cmd" value="<?php echo @htmlspecialchars ( stripslashes ( $_POST['cmd'] ) ); ?>" size="50" />
        <button type="submit" name="submit" id="submit" value="Submit">Submit</button>
      </p>
    </form>


    <?php if ( isset ( $cmd ) ) : ?>
    <fieldset><legend><?php echo htmlspecialchars($cmd); ?></legend>
      <pre id="response"><?php var_dump($repsonse); ?></pre>
    </fieldset>
    <?php endif; ?>
  </body>
</html>

Upvotes: 1

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