Reputation: 1241
How do I handle categorical data with spark-ml
and not spark-mllib
?
Thought the documentation is not very clear, it seems that classifiers e.g. RandomForestClassifier
, LogisticRegression
, have a featuresCol
argument, which specifies the name of the column of features in the DataFrame
, and a labelCol
argument, which specifies the name of the column of labeled classes in the DataFrame
.
Obviously I want to use more than one feature in my prediction, so I tried using the VectorAssembler
to put all my features in a single vector under featuresCol
.
However, the VectorAssembler
only accepts numeric types, boolean type, and vector type (according to the Spark website), so I can't put strings in my features vector.
How should I proceed?
Upvotes: 49
Views: 66773
Reputation: 1
I use the following method for oneHotEncoding a single column in a Spark dataFrame:
def ohcOneColumn(df, colName, debug=False):
colsToFillNa = []
if debug: print("Entering method ohcOneColumn")
countUnique = df.groupBy(colName).count().count()
if debug: print(countUnique)
collectOnce = df.select(colName).distinct().collect()
for uniqueValIndex in range(countUnique):
uniqueVal = collectOnce[uniqueValIndex][0]
if debug: print(uniqueVal)
newColName = str(colName) + '_' + str(uniqueVal) + '_TF'
df = df.withColumn(newColName, df[colName]==uniqueVal)
colsToFillNa.append(newColName)
df = df.drop(colName)
df = df.na.fill(False, subset=colsToFillNa)
return df
I use the following method for oneHotEncoding Spark dataFrames:
from pyspark.sql.functions import col, countDistinct, approxCountDistinct
from pyspark.ml.feature import StringIndexer
from pyspark.ml.feature import OneHotEncoderEstimator
def detectAndLabelCat(sparkDf, minValCount=5, debug=False, excludeCols=['Target']):
if debug: print("Entering method detectAndLabelCat")
newDf = sparkDf
colList = sparkDf.columns
for colName in sparkDf.columns:
uniqueVals = sparkDf.groupBy(colName).count()
if debug: print(uniqueVals)
countUnique = uniqueVals.count()
dtype = str(sparkDf.schema[colName].dataType)
#dtype = str(df.schema[nc].dataType)
if (colName in excludeCols):
if debug: print(str(colName) + ' is in the excluded columns list.')
elif countUnique == 1:
newDf = newDf.drop(colName)
if debug:
print('dropping column ' + str(colName) + ' because it only contains one unique value.')
#end if debug
#elif (1==2):
elif ((countUnique < minValCount) | (dtype=="String") | (dtype=="StringType")):
if debug:
print(len(newDf.columns))
oldColumns = newDf.columns
newDf = ohcOneColumn(newDf, colName, debug=debug)
if debug:
print(len(newDf.columns))
newColumns = set(newDf.columns) - set(oldColumns)
print('Adding:')
print(newColumns)
for newColumn in newColumns:
if newColumn in newDf.columns:
try:
newUniqueValCount = newDf.groupBy(newColumn).count().count()
print("There are " + str(newUniqueValCount) + " unique values in " + str(newColumn))
except:
print('Uncaught error discussing ' + str(newColumn))
#else:
# newColumns.remove(newColumn)
print('Dropping:')
print(set(oldColumns) - set(newDf.columns))
else:
if debug: print('Nothing done for column ' + str(colName))
#end if countUnique == 1, elif countUnique other condition
#end outer for
return newDf
Upvotes: 0
Reputation: 1197
You can cast a string column type in a spark data frame to a numerical data type using the cast function.
from pyspark.sql import SQLContext
from pyspark.sql.types import DoubleType, IntegerType
sqlContext = SQLContext(sc)
dataset = sqlContext.read.format('com.databricks.spark.csv').options(header='true').load('./data/titanic.csv')
dataset = dataset.withColumn("Age", dataset["Age"].cast(DoubleType()))
dataset = dataset.withColumn("Survived", dataset["Survived"].cast(IntegerType()))
In the above example, we read in a csv file as a data frame, cast the default string datatypes into integer and double, and overwrite the original data frame. We can then use the VectorAssembler to merge the features in a single vector and apply your favorite Spark ML algorithm.
Upvotes: -2
Reputation: 40370
I just wanted to complete Holden's answer.
Since Spark 2.3.0,OneHotEncoder
has been deprecated and it will be removed in 3.0.0
. Please use OneHotEncoderEstimator
instead.
In Scala:
import org.apache.spark.ml.Pipeline
import org.apache.spark.ml.feature.{OneHotEncoderEstimator, StringIndexer}
val df = Seq((0, "a", 1), (1, "b", 2), (2, "c", 3), (3, "a", 4), (4, "a", 4), (5, "c", 3)).toDF("id", "category1", "category2")
val indexer = new StringIndexer().setInputCol("category1").setOutputCol("category1Index")
val encoder = new OneHotEncoderEstimator()
.setInputCols(Array(indexer.getOutputCol, "category2"))
.setOutputCols(Array("category1Vec", "category2Vec"))
val pipeline = new Pipeline().setStages(Array(indexer, encoder))
pipeline.fit(df).transform(df).show
// +---+---------+---------+--------------+-------------+-------------+
// | id|category1|category2|category1Index| category1Vec| category2Vec|
// +---+---------+---------+--------------+-------------+-------------+
// | 0| a| 1| 0.0|(2,[0],[1.0])|(4,[1],[1.0])|
// | 1| b| 2| 2.0| (2,[],[])|(4,[2],[1.0])|
// | 2| c| 3| 1.0|(2,[1],[1.0])|(4,[3],[1.0])|
// | 3| a| 4| 0.0|(2,[0],[1.0])| (4,[],[])|
// | 4| a| 4| 0.0|(2,[0],[1.0])| (4,[],[])|
// | 5| c| 3| 1.0|(2,[1],[1.0])|(4,[3],[1.0])|
// +---+---------+---------+--------------+-------------+-------------+
In Python:
from pyspark.ml import Pipeline
from pyspark.ml.feature import StringIndexer, OneHotEncoderEstimator
df = spark.createDataFrame([(0, "a", 1), (1, "b", 2), (2, "c", 3), (3, "a", 4), (4, "a", 4), (5, "c", 3)], ["id", "category1", "category2"])
indexer = StringIndexer(inputCol="category1", outputCol="category1Index")
inputs = [indexer.getOutputCol(), "category2"]
encoder = OneHotEncoderEstimator(inputCols=inputs, outputCols=["categoryVec1", "categoryVec2"])
pipeline = Pipeline(stages=[indexer, encoder])
pipeline.fit(df).transform(df).show()
# +---+---------+---------+--------------+-------------+-------------+
# | id|category1|category2|category1Index| categoryVec1| categoryVec2|
# +---+---------+---------+--------------+-------------+-------------+
# | 0| a| 1| 0.0|(2,[0],[1.0])|(4,[1],[1.0])|
# | 1| b| 2| 2.0| (2,[],[])|(4,[2],[1.0])|
# | 2| c| 3| 1.0|(2,[1],[1.0])|(4,[3],[1.0])|
# | 3| a| 4| 0.0|(2,[0],[1.0])| (4,[],[])|
# | 4| a| 4| 0.0|(2,[0],[1.0])| (4,[],[])|
# | 5| c| 3| 1.0|(2,[1],[1.0])|(4,[3],[1.0])|
# +---+---------+---------+--------------+-------------+-------------+
Since Spark 1.4.0, MLLib also supplies OneHotEncoder feature, which maps a column of label indices to a column of binary vectors, with at most a single one-value.
This encoding allows algorithms which expect continuous features, such as Logistic Regression, to use categorical features
Let's consider the following DataFrame
:
val df = Seq((0, "a"),(1, "b"),(2, "c"),(3, "a"),(4, "a"),(5, "c"))
.toDF("id", "category")
The first step would be to create the indexed DataFrame
with the StringIndexer
:
import org.apache.spark.ml.feature.StringIndexer
val indexer = new StringIndexer()
.setInputCol("category")
.setOutputCol("categoryIndex")
.fit(df)
val indexed = indexer.transform(df)
indexed.show
// +---+--------+-------------+
// | id|category|categoryIndex|
// +---+--------+-------------+
// | 0| a| 0.0|
// | 1| b| 2.0|
// | 2| c| 1.0|
// | 3| a| 0.0|
// | 4| a| 0.0|
// | 5| c| 1.0|
// +---+--------+-------------+
You can then encode the categoryIndex
with OneHotEncoder
:
import org.apache.spark.ml.feature.OneHotEncoder
val encoder = new OneHotEncoder()
.setInputCol("categoryIndex")
.setOutputCol("categoryVec")
val encoded = encoder.transform(indexed)
encoded.select("id", "categoryVec").show
// +---+-------------+
// | id| categoryVec|
// +---+-------------+
// | 0|(2,[0],[1.0])|
// | 1| (2,[],[])|
// | 2|(2,[1],[1.0])|
// | 3|(2,[0],[1.0])|
// | 4|(2,[0],[1.0])|
// | 5|(2,[1],[1.0])|
// +---+-------------+
Upvotes: 59
Reputation: 1288
I am going to provide an answer from another perspective, since I was also wondering about categorical features with regards to tree-based models in Spark ML (not MLlib), and the documentation is not that clear how everything works.
When you transform a column in your dataframe using pyspark.ml.feature.StringIndexer
extra meta-data gets stored in the dataframe that specifically marks the transformed feature as a categorical feature.
When you print the dataframe you will see a numeric value (which is an index that corresponds with one of your categorical values) and if you look at the schema you will see that your new transformed column is of type double
. However, this new column you created with pyspark.ml.feature.StringIndexer.transform
is not just a normal double column, it has extra meta-data associated with it that is very important. You can inspect this meta-data by looking at the metadata
property of the appropriate field in your dataframe's schema (you can access the schema objects of your dataframe by looking at yourdataframe.schema)
This extra metadata has two important implications:
When you call .fit()
when using a tree based model, it will scan the meta-data of your dataframe and recognize fields that you encoded as categorical with transformers such as pyspark.ml.feature.StringIndexer
(as noted above there are other transformers that will also have this effect such as pyspark.ml.feature.VectorIndexer
). Because of this, you DO NOT have to one-hot encode your features after you have transformed them with StringIndxer when using tree-based models in spark ML (however, you still have to perform one-hot encoding when using other models that do not naturally handle categoricals like linear regression, etc.).
Because this metadata is stored in the data frame, you can use pyspark.ml.feature.IndexToString
to reverse the numeric indices back to the original categorical values (which are often strings) at any time.
Upvotes: 50
Reputation: 7452
There is a component of the ML pipeline called StringIndexer
you can use to convert your strings to Double's in a reasonable way. http://spark.apache.org/docs/latest/api/scala/index.html#org.apache.spark.ml.feature.StringIndexer has more documentation, and http://spark.apache.org/docs/latest/ml-guide.html shows how to construct pipelines.
Upvotes: 7