CODEWITHSUNDEEP
c#telegram-bot
sma6871
sma6871

Reputation: 3298

Send Photo Telegram API

I want to send a photo using the Telegram.Bot library, but it's not working!

Here is my code:

private void btnSendImage_Click(object sender, RoutedEventArgs e)
    {
        var Bot = new Telegram.Bot.Api(token);

        Task<Telegram.Bot.Types.Update[]> res = Bot.GetUpdates();

        List<string> users = GetIds();
        foreach (var update in res.Result)
        {
            if (!users.Contains("" + update.Message.Chat.Id))
            {
                AddId("" + update.Message.Chat.Id);

            }
        }
        users = GetIds();
        foreach (var item in users)
        {
            if (item.Length > 0)
            {

                var rep = Bot.SendPhoto(Convert.ToInt32(item), txtImagePath.Text, txtMessage.Text);
            }
        }

    }

and txtImagePath.text= "D:\Projects\Telegram Bot\Telegram Bot\bin\Debug\4.jpg";

I tested it with Bot.SendMessage and it worked fine, but I can't send a photo!

Upvotes: 4

Views: 16925

Answers (2)

8611670474
8611670474

Reputation: 344

I used this code and it's worked!

var FileUrl = @"C:\\Users\\User\\Documents\\20160201_204055.jpg";
using (var stream = System.IO.File.Open(FileUrl, FileMode.Open))
        {
            FileToSend fts = new FileToSend();
            fts.Content = stream;
            fts.Filename = FileUrl.Split('\\').Last();
            var test = await bot.SendPhoto("@channel Name or chat_id", fts, "My Text");
        }

Upvotes: 7

Robin M&#252;ller
Robin M&#252;ller

Reputation: 41

you need to pass a Stream to the function if you want to send an new image.

using (var stream = File.Open(txtImagePath.Text, FileMode.Open))
{
    var rep = await Bot.SendPhoto(Convert.ToInt32(item), stream, txtMessage.Text);
}

Upvotes: 2

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