CODEWITHSUNDEEP
regex
James
James

Reputation: 139

Regular expression regex help; ignore random blocks of data

I am doing a regex search on binary files, and I've just discovered a problem, every so often, a 64 byte checksum is used, which throws my searches out. What I want to know is; is there a way to ignore these 64bytes, regardless of where they appear in my data?

My regex is \x18\xC0\x40[\x42\x43][\x00\x01]\x00\x00\x00

my problem is illustrated below;

0230000000FF45198085B918C0404301

FFFFFFFFFFFFFFFFC03CCFFFFFFFFFFF

FFFFFFFFFFFFFFFF3C0CFFFFFFFFFFFF

FFFFFFFFFFFFFFFF0300F0FFFFFFFFFF

FFFFFFFFFFFFFFFF030F0FFFFFFF4700

000000B9000000003C8085B9EDDF0000

In my example, my regex (values needed in bold) obviously doesn't pick up my pattern match. This can happen at any point in the required data as well.

An observation for the checksum data is it always ends 4700, and it is always 8 bytes of FF, followed by 3-4 bytes of values, followed by 4-5 bytes of FF again.

Any help would be greatly appreciated, thanks James

Upvotes: 2

Views: 591

Answers (3)

Toto
Toto

Reputation: 91438

Try this :

\x18\xC0\x40[\x42\x43][\x00\x01](?:\x00{8}[\x00-\xFF]*?\x47\x00)\x00{3}

Updated, this will work if checksum is everywhere. I inserted linefeeds for readability

\x18(?:\x00{8}[\x00-\xFF]*?\x47\x00)
\xC0(?:\x00{8}[\x00-\xFF]*?\x47\x00)
\x40(?:\x00{8}[\x00-\xFF]*?\x47\x00)
[\x42\x43](?:\x00{8}[\x00-\xFF]*?\x47\x00)
[\x00\x01](?:\x00{8}[\x00-\xFF]*?\x47\x00)
\x00(?:\x00{8}[\x00-\xFF]*?\x47\x00)
\x00(?:\x00{8}[\x00-\xFF]*?\x47\x00)
\x00

Upvotes: 1

Jens
Jens

Reputation: 25563

You should probably use two passes for your search. In the first pass you delete all these checksum block, which should be easy enough to identify, in the second pass you do your actual search.

Otherwise, you'd have to allow for a checksum block after each letter of your expression, resulting in a very long and hard to read one.

Upvotes: 2

Erik
Erik

Reputation: 3777

\x18\xC0\x40[\x42\x43][\x00\x01][^\x00\x00\x00]*\x00\x00\x00

Upvotes: 1

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