CODEWITHSUNDEEP
c++string
ice cream in winter
ice cream in winter

Reputation: 27

String and ascii values

In this piece of code if i run a for loop to know elements stored inside the array c I get output as 1 1 1 0 0 0 0 1 0 0.

The input is abc. Why it does it give 1 1 1 instead of 0 1 2 0 0 0 0 0 0?

int c[26]={};
cin >> s;
len = s.length();
for(int i = 0 ; i < len ; i++ ){
    c[s[i] - 'a'] ++ ;
}

Upvotes: 0

Views: 70

Answers (3)

Abend
Abend

Reputation: 589

s[i] - 'a'

That is returning 0, 1 and 2. But

c[s[i] - 'a'] ++ ;

Is always increasing 1 each occurrence of C[] which at the beginning was initializing with all zeros. For that reason you get all 1s in your output.

Try 

c[s[i] - 'a'] = s[i] - 'a'

Upvotes: 0

Michael Albers
Michael Albers

Reputation: 3779

Your c array is a histogram of the characters read. Your output is saying you read 1 'a', 1 'b' and 1 'c'. Try c[s[i] - 'a'] = s[i] - 'a';

Upvotes: 1

Shoe
Shoe

Reputation: 76240

Your code is basically counting the number of letters in a string. The count is stored in the array c where the index represents the letter index in the alphabet. So a is 0, b is 1, c is 2 and so on.

So for abc the correct input is indeed 1 1 1, due to the fact that there's 1 a, 1 b and 1 c. Your 0 1 2 would represent a string with 1 b and 2 cs.

Upvotes: 0

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