Reputation: 561
I am not able to figure out what does &p do in the below script. and does print -u4
mean that whatever argument passed is written in file decriptor 4?
1: $SRVRMGRCMD |&
3: BGPID=$!
4: exec 4>&p
5: exec 5<&p
6: sleep 2
7: # Build a list of Servers
8: print -u4 "list servers show SBLSRVR_NAME"
Thanks in advance.
Upvotes: 1
Views: 413
Reputation: 11267
What language is that?
If it's bash or a shell, it creates a file descriptor to store the output, see here:
http://www.softpanorama.org/Tools/exec.shtml, specifically this part:
exec 3< inputfile # Opens inputfile with file descriptor 3 for reading.
exec 4> outputfile # Opens outputfile with file descriptor 4 for writing.
exec 5<&0 # Makes fd 5 a copy of fd 0 (standard input).
exec 6>&p # Attach fd 6 to co-process.
Edited to say:
The -un says to write all output to the file descriptor n
See here http://alasir.com/books/bsd/428-430.html
Upvotes: 1
Reputation: 621
These appear to be references to co-processes (in ksh or zsh).
see https://unix.stackexchange.com/questions/86270/how-do-you-use-the-command-coproc-in-bash
Upvotes: 1