CODEWITHSUNDEEP
iosxcodeswiftparse-platformpfquery
kareem
kareem

Reputation: 933

save string to parse array in swift

I have a column in my parse table that i want to store names in when a user accepts another user, so it is one string at a time.

The column is called "passengers" and the string I am trying to store is an Id.

I successfully get the correct Id but saving it to the column in parse is my problem.

Here is my code 

   var appendToPassengerArrayQuery = PFQuery(className: "Posts")
                        appendToPassengerArrayQuery.getObjectInBackgroundWithId(cell.postIdLabel.text!, block: {
                            (object:PFObject?, error: NSError?) -> Void in


                          // this is where I want to send the id to the array in the column of the correct post
                           object["passengers"] = userId
                            object?.saveInBackgroundWithBlock{
                                (success: Bool, error: NSError?)-> Void in
                            if (success) {
                                println("request deleted")

                            }
                            else {
                                println("cannot delete")
                                }}
                        })

The error I am getting is on the line object["passengers"] = userId

This is the error message cannot assign value type string to a value of type anyobject

Upvotes: 1

Views: 1108

Answers (1)

Santhosh
Santhosh

Reputation: 691

The reason you are getting the error is because object: PFObject? is still unwrapped which means its value can be a nil or PFObject.

    var appendToPassengerArrayQuery = PFQuery(className: "Posts")
    appendToPassengerArrayQuery.getObjectInBackgroundWithId(cell.postIdLabel.text!, block: {
        (object:PFObject?, error: NSError?) -> Void in
        if object != nil {
            object!["passengers"] = userId
            object!.saveInBackgroundWithBlock{
                (success: Bool, error: NSError?)-> Void in
                if (success) {
                    println("request deleted")
                }
                else {
                    println("cannot delete")
                }}
        }
    })

Upvotes: 2

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