CODEWITHSUNDEEP
phpjqueryajax
Jitesh Sojitra
Jitesh Sojitra

Reputation: 4043

Getting Ajax script response in PHP variable

I have three php files.

main.php - to use stored Ajax response.
filter.php - to send Ajax request and get response
insert.php - to store Ajax response for using in main.php

Primary purpose of doing all these thing is to use client side values using PHP code because server and client can't exchange variable values each other.

The response should be stored in php variable in main.php.

main.php:

?>

<script>
$.ajax({
 type: "POST",
 url: "filter.php",
 data: { id1: name, id2:"employees"},


  success:function(response) {
    var res = response;
    $.ajax({
        type: "POST",
        url: "insert.php",
        data: { id1: res },

    success:function(data){
      alert(data);
      }
   });
});
<script>

<?php

$ajaxResponse = ???? <need to get value of data over here>

filter.php:

// Return employee names

    if ($_POST['id1'] == "name" && $_POST['id2'] == "employees") {

        $conn = mysqli_connect (DB_HOST, DB_USER, DB_PASSWORD, DB_NAME);
        if ($conn->connect_error) {
            die("Connection failed: " . $conn->connect_error);
        }

        $sql = "SELECT " .$_POST['id1']. " FROM 1_employees";
        $result = mysqli_query($conn, $sql);
        if (mysqli_num_rows($result) > 0) {
            while($row =  mysqli_fetch_array($result)) {
                $rows[] = $row['name'];
            }
        }

        echo json_encode($rows);

        mysqli_close($conn);

        exit (0);

    }

insert.php:

if ($_POST) {

    if ($_POST['id1'] !== "") {

        echo $_POST['id1'];

    }

}

So how can I get ajax response value in main.php at $ajaxResponse = ?????

Upvotes: 0

Views: 14069

Answers (4)

Feshibaba
Feshibaba

Reputation: 101

The answer is to simply use Javascript to store the response from Ajax into a hidden variable and make use of that for further action. That solved my query and I'm sure many will actually need this too!

Upvotes: 0

Jitesh Sojitra
Jitesh Sojitra

Reputation: 4043

Here is the answer:

Get names in main.php using below way:

-------- filter.php ----------

session_start(); //at the top
$_SESSION['names'] = json_encode($rows);

-------- main.php ----------

session_start();
$issued_to = explode(",", $names);

session_unset();
session_destroy();

Upvotes: 0

Jai
Jai

Reputation: 74748

You can't use it that way.

Why:

javascript/jQuery is a scripting language which runs in browser when DOM is fully loaded and elements are available to make selectors.

While php is serverside language which runs on server way before page load.

So in short you can't assign a ajax response to a php variable.

one thing you can do to have a hidden input and put the response value in it and you can get that value to use it.

success:function(data){
  alert(data);
  $('#hiddenInputId').val(data); // set the response data to the hidden input and use it.
}

Upvotes: 2

Rajesh kannan
Rajesh kannan

Reputation: 634

You can create a div where you want to display the response contents

in your case it is after <script> tag

And use innerHTML to display the contents

Use this code

<script>
$.ajax({
 type: "POST",
 url: "filter.php",
 data: { id1: name, id2:"employees"},


  success:function(response) {
    var res = response;
    $.ajax({
        type: "POST",
        url: "insert.php",
        data: { id1: res },

    success:function(data){
      $("#responseContent").html(data);
      }
   });
});
<script>
<div id="responseContent"></div>

Let me know if it is helpful

Upvotes: 1

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