CODEWITHSUNDEEP
windowsbatch-file
Smij01
Smij01

Reputation: 45

echo variable is not working in batch file

My batch file execution throws error at echo echo %outfvar%. The following is the batch file I wrote:

setlocal ENABLEDELAYEDEXPANSION
set /a incvar = 1
set outfvar = "outfile"_!incvar!".res"
echo !outfvar!
echo *.txt > !outfvar!
set /a incvar = incvar+1

FOR %%pat in (%*) do(
    FOR /F %%k in (!outfvar!) DO( grep -l !pat! !k! >>outfile_!incvar!.res)
    set /a incvar = incvar+1
    set outfvar = "outfile"_!incvar!.res
                     )

Error is "%pat was unexpected at this time.." Can anybody help me to execute this batch file successfully?

Upvotes: 0

Views: 172

Answers (1)

aschipfl
aschipfl

Reputation: 34899

Remove the spaces around = in all set commands.

There must be a space in between do and ( in the line of for.

The line

set outfvar = "outfile"_%incvar%".res"

should read

set "outfvar=outfile_%incvar%.res"

(The quotes as you stated them were part of the string value.)

for variables must consist of one letter only and need to be expanded by preceding with %%. You are trying to use %%pat in your code, which will not work. State %%p instead (also inner for).

Finally, you need delayed expansion to be able to read variables you modify within the same (compound) command, the for in your code. See this post to learn how it works.

Upvotes: 3

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