CODEWITHSUNDEEP
pythondjango
Manish Gupta
Manish Gupta

Reputation: 4656

django not returning appropriate response

I have a template with checkbox and a button. I want , when i select all checkbox and press the button it should return the values and display it as a httpresponse.

Index.html:

<form method="POST" action="/test/">
    {% csrf_token %}
    <div id="row-1">
        <button name="pack" id="pack">Pack</button>
    </div>
    <div id="row-2">
        <table>
            <thead>
                <tr>
                    <th><input type="checkbox" onClick="toggle(this, 'no')"></th>
                    <th>Order Id</th>
                </tr>
            </thead>
            <tbody>
                <tr>
                    <td><input type="checkbox" name="no" value="10000001">10000001</td>
                </tr>
                <tr>
                    <td><input type="checkbox" name="no" value="10000002">10000002</td>
                </tr>
            </tbody>
        </table>
    </div>
</form>

views.py:

from django.shortcuts import render, render_to_response
from django.http import HttpResponse
from test1 import forms

def index(request):
    return render(request, 'index.html')

def pack(request):
    oid_list = []
    form = forms.PackOrders(request.POST or None)
    if request.method == 'POST':
        for item in form.cleaned_data['no']:
            oid_list.append(item)
    return HttpResponse(','.join(oid_list))

urls.py:

from django.conf.urls import patterns
from django.conf.urls import url
from test1 import views

urlpatterns = patterns('',
    url(r'^$', views.index, name='index'),
    url(r'^test/', views.pack, name='pack'),)

forms.py:

from django import forms

class PackOrders(forms.Form):
    order_items = forms.CharField()

The problem is that when i cleck the checkbox and i return the code it just reload the index.html instead of displaying the values of checkbox.

Expected Output:

10000001,10000002

What is wrong with the code?

EDIT :

projects urls.py:

from django.conf.urls import include, url
from django.contrib import admin

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$', include('test1.urls')),
    url(r'^test/', include('test1.urls')),
]

Upvotes: 0

Views: 65

Answers (2)

Daniel Roseman
Daniel Roseman

Reputation: 599590

You've included your app urlconf into your root urlconf twice. You should only do it once. However, you should remove the $ from the URL that includes it:

url(r'^', include('test1.urls')),

If you used the second version instead, with the 'test/' prefix, you would create URLs at '/test/' and '/test/test/', which presumably isn't what you want.

Note though that as I said in the comment, you should always reference URLs via their name, not directly. So your form action should be "{% url 'pack' %}".

Upvotes: 2

Sayse
Sayse

Reputation: 43300

$ in regex indicates the end of the string so your include will never get chance to match any of its urls (which I imagine is what your other urls.py is). Therefore you need to change your urls to the included urls

urlpatterns = [
    url(r'^admin/', include(admin.site.urls)),
    url(r'^/', include('test1.urls')),
    url(r'^test/', include('test1.urls')),
]

Notice I have changed the second one to remove the $ and replace it with a slash

Upvotes: 0

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