CODEWITHSUNDEEP
scalaapache-flink
sthiers
sthiers

Reputation: 3531

How to use flink fold function in scala

This is a non working try for using Flink fold with scala anonymous function:

val myFoldFunction = (x: Double, t:(Double,String,String)) => x + t._1
env.readFileStream(...).
...
.groupBy(1)
.fold(0.0, myFoldFunction : Function2[Double, (Double,String,String), Double])

It compiles well, but at execution, I get a "type erasure issue" (see below). Doing so in Java is fine, but of course more verbose. I like the concise and clear lambdas. How can I do that in scala?

Caused by: org.apache.flink.api.common.functions.InvalidTypesException:
Type of TypeVariable 'R' in 'public org.apache.flink.streaming.api.scala.DataStream org.apache.flink.streaming.api.scala.DataStream.fold(java.lang.Object,scala.Function2,org.apache.flink.api.common.typeinfo.TypeInformation,scala.reflect.ClassTag)' could not be determined. 
This is most likely a type erasure problem. 
The type extraction currently supports types with generic variables only in cases where all variables in the return type can be deduced from the input type(s).

Upvotes: 5

Views: 637

Answers (1)

Till Rohrmann
Till Rohrmann

Reputation: 13346

The problem you encountered is a bug in Flink [1]. The problem originates from Flink's TypeExtractor and the way the Scala DataStream API is implemented on top of the Java implementation. The TypeExtractor cannot generate a TypeInformation for the Scala type and thus returns a MissingTypeInformation. This missing type information is manually set after creating the StreamFold operator. However, the StreamFold operator is implemented in a way that it does not accept a MissingTypeInformation and, consequently, fails before setting the right type information.

I've opened a pull request [2] to fix this problem. It should be merged within the next two days. By using then the latest 0.10 snapshot version, your problem should be fixed.

Upvotes: 3

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