Reputation: 369
I have a URL like: https://website.org/withdraw.php?valid_addr=1333mwKE7EcwLaR9ztdtEt7pPEfafpW4nn&amount=0.0002&_unique=1
and A line of code that reads:
if (empty($_GET['amount']) || empty($_GET['valid_addr']) || empty($_GET['_unique']))==0) exit();
If I remove the line then the code runs successfully. Can anyone tell me what I've done wrong.
The line is supposed to stop the code from running if any of the three fields are left empty.
Thanks.
Upvotes: 0
Views: 153
Reputation: 101
if (($_GET['amount'] == 0) OR ($_GET['valid_addr'] == 0) OR ($_GET['_unique'] == 0)) { exit(); }
Upvotes: 1
Reputation: 308
Above your code has syntax error. I think you want to validate unique with 0 and 1. So you should have to try this code
if (empty($_GET['amount']) || empty($_GET['valid_addr']) || $_GET['_unique'])==0) exit();
Upvotes: 0
Reputation: 1082
You're code should be something like this:
if (empty($_GET['amount']) || empty($_GET['valid_addr']) || empty($_GET['_unique']))
{
exit();
}
Upvotes: 0
Reputation: 2698
Syntax Error. Remove the ==0)
part:
if(empty($_GET['amount']) || empty($_GET['valid_addr']) || empty($_GET['_unique'])) {
exit();
}
Upvotes: 0
Reputation: 7573
I think you want to utilize array_key_exists
rather than empty.
if (!array_key_exists('amount', $_GET) ||
!array_key_exists('valid_addr', $_GET) ||
!array_key_exists('_unique', $_GET))
exit();
From PHP empty() docs
Determine whether a variable is considered to be empty. A variable is considered empty if it does not exist or if its value equals FALSE. empty() does not generate a warning if the variable does not exist.
Upvotes: 2
Reputation: 919
Left parenthesis missing,
if ((empty($_GET['amount']) || empty($_GET['valid_addr']) || empty($_GET['_unique']))==0) exit();
Try it...
Upvotes: 0