Reputation:
dic = {('UUU','UUC'):'F',('GUU','GUC','GUA','GUG'):'V'}
L = ['UUU', 'GUG', 'GUU']
As you see each elements of list(L) are in dictionary as keys. Now i want to replace each elements of L by its corresponding values. Output would be:
output = ['F','V']
How can i do that?
Upvotes: 0
Views: 30
Reputation: 28425
Using list compression:
In [1]: dic = {('UUU','UUC'):'F',('GUU','GUC','GUA','GUG'):'V'}
In [2]: L = ['UUU', 'GUG', 'GUU']
In [3]: list(set([v for k,v in dic.items() for x in L if x in k]))
Out [3]: ['V', 'F']
Upvotes: 1
Reputation: 600059
One way would be to decompose the keys into individual elements, and create a new dict from those:
new_dic = {}
for k, v in dic.items():
for sub_k in k:
new_dic[sub_k] = v
Now it's a simple matter of looping through the list:
output = [new_dic[i] for i in L]
and you can de-duplicate with set
:
output = list(set(output))
Upvotes: 1