CODEWITHSUNDEEP
javascriptnode.jssocketswebsocketsocket.io
ujwal dhakal
ujwal dhakal

Reputation: 2469

Node js connecting two socket so that retrieving would be easier

Currently now i am using io.emit where i send the event to all the connected users and in client side i check whether the id of user i emit is equal to the id of client side then the condition runs i thinks its making my code messy and bit slow is there anything i can do like connecting then in one group so when retrieving them i would be easier for me.

//server side
var id = 1;
io.emit('check',id);

// on client side 
socket.on('check',function(data){
var current_user_login = //getting current user login id by php
if(data == current_user_login) { 
//run some code
}
});

Upvotes: 0

Views: 44

Answers (2)

jfriend00
jfriend00

Reputation: 707786

The better way to solve this problem is to create an association between the user you want to send the data to and that user's socket so you can .emit() only to that particular socket. This is much, much more efficient than sending to everyone especially when you have lots of connected sockets.

You would have to explain to us much more about how you know which socket or user you want to send to in order for us to help figure out how to do that association in your server.

socket.io has the concept of "rooms" which are groups of sockets that makes it easy for you to place a socket in a specific group and to then broadcast to a specific group of sockets.

Or, each socket has an id and each socket has access to the cookies that were present when the connection was first made, both of which can sometimes be used to identify which user you want to send to. But, you'd have to explain how you know which user you want to send to for us to help give you an idea how to code that into your server.

Upvotes: 1

havish
havish

Reputation: 373

If you want to put certain sockets in the same room, so that it's easy to broadcast to all of them together. Try this:

var io = require('socket.io').listen(80);

io.sockets.on('connection', function (socket) {
  socket.join('group');
  socket.broadcast.to('group').emit('new member');
});

Hope this helps.

Upvotes: 1

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