Reputation: 66565
Looking for a solution to this problem I have tried to follow several procedures suggested so far on SO but neither worked.
I want to select a random number of random unique items from selected array. In order to do that, I've written the following function, which always returns duplicates instead of unique items:
function getRandomItemsCombination(min, max, sourceArray){
var items = {};
//var itemsCount = Math.floor(Math.random() * (max - min + 1)) + min;
var itemsCount = random.integer(min, max);
//var randomItem = getRandomArrayElement(sourceArray);
var randomItem;
var arrIntegers = []
while(arrIntegers.length < itemsCount){
var randomnumber=Math.ceil(Math.random()*(sourceArray.length - 1))
var found=false;
for(var i=0;i<arrIntegers.length;i++){
if(arrIntegers[i]==randomnumber){found=true;break}
}
if(!found)arrIntegers[arrIntegers.length]=randomnumber;
}
items.items = [];
var randomItemsIndex = {};
items.quantities = [];
var existing = false;
for(var i = 0; i < itemsCount; i++){
randomItem = sourceArray[arrIntegers[i]];
var index = randomItemsIndex[randomItem.Long_desc];
if(index == undefined){
index = items.items.length;
randomItemsIndex[randomItem.Long_desc] = index;
existing = false;
}
else {
existing = true;
}
items.items[index] = randomItem;
existing = false;
}
return items;
}
Does anyone know why it doesn't return unique items?
Thanks!
Upvotes: 0
Views: 89
Reputation: 8765
You can use underscorejs sample
function
_.sample(list, [n])
Produce a random sample from the list. Pass a number to return n random elements from the list. Otherwise a single random item will be returned.
_.sample([1, 2, 3, 4, 5, 6]);
=> 4
_.sample([1, 2, 3, 4, 5, 6], 3);
=> [1, 6, 2]
http://underscorejs.org/#sample
Upvotes: 2