Reputation: 35
When the input is 25
the expected output is 15511210043330985984000000
and not 1.551121e+25
. The parsing though is solved by Decimal.Parse(factorial.ToString(), System.Globalization.NumberStyles.Float)
.
I cannot get to calcuate for bigger numbers like 95.
using System;
namespace bigNumber
{
class Program
{
static void Main(string[] args)
{
int number = Convert.ToInt32(Console.ReadLine());
long factorial = 1;
for (int i = number; i > 0; i--)
{
factorial = factorial * i;
}
Console.WriteLine(factorial);
}
}
}
Upvotes: 3
Views: 975
Reputation: 186803
You have to use BigInteger
in your solution:
using System.Numerics;
using System.Linq;
...
int n = 95;
BigInteger factorial = Enumerable
.Range(1, n)
.Select(x => (BigInteger) x)
.Aggregate((f, v) => f * v);
Console.WriteLine(factorial);
Answer is
10329978488239059262599702099394727095397746340117372869212250571234293987594703124871765375385424468563282236864226607350415360000000000000000000000
note, that the factorial
is far beyond long.MaxValue
Upvotes: 4
Reputation: 2309
As stated above, the BigInteger is a good candidate, as it can hold an arbitrarily large signed integer:
namespace ConsoleApplication4
{
using System;
using System.Numerics;
class Program
{
static void Main(string[] args)
{
Console.WriteLine(Factorial(0));
Console.WriteLine(Factorial(25));
Console.WriteLine(Factorial(95));
}
private static BigInteger Factorial(int number)
{
BigInteger factorial = 1;
for (var i = number; i > 0; i--)
{
factorial *= i;
}
return factorial;
}
}
}
1
15511210043330985984000000
10329978488239059262599702099394727095397746340117372869212250571234293987594703124871765375385424468563282236864226607350415360000000000000000000000
Press any key to continue . . .
Upvotes: 3
Reputation: 49
The BigInteger class from .Net 4.0+ supports arbitrarily large integers, int is relatively limiting in how many significant digits it represents.
Upvotes: 1