CODEWITHSUNDEEP
arraysbashvariablesiterationuser-input
awright19
awright19

Reputation: 13

Returning the next item in an array based on user input

I am requesting user input using read. I would like to match the input to an array, and if it matches, print the next item in the array.

For example:

echo "What day of the week is it?"
read day
for d in "$(week[@])" do
if [ "$d" == "$day" ]; then
echo "The next day of the week is ${week [d++]}."
fi
done

I would only like to print the very next day. (So if the user inputs 'Wednesday' I would like only 'Thursday' to be returned. With the script above only the day 'Monday' is returned.

Upvotes: 1

Views: 71

Answers (2)

pacholik
pacholik

Reputation: 8972

Just loop over the array by index until you find the day and increase the index again after the loop.

week=(Su Mo Tu We Th Fr Sa Su)  # another Su at the end
read day

i=0
until [[ ${week[i]} == $day ]]; do
    let i++
done

echo ${week[++i]}

Upvotes: 1

Mahesh Kharvi
Mahesh Kharvi

Reputation: 399

week=(Sun Mon Tue Wed Thu Fri Sat)

i=0
for str in ${week[@]}; do
  if [[ $str = "$day" ]]; then
         i=$(((i+1)%7))                #Get index 0 if day is saturday
         echo "Next day is ${week[i]}" 
        break 
    fi
     i=$((i+1)) 
done

Upvotes: 0

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