Reputation: 13
I was using the following code to send fromData contains 2 values (File and String) to a WebAPI using javascript.
var formData = new FormData();
formData.append('name', 'previewImg');
formData.append('upload', $('input[type=file]')[0].files[0]);
$.ajax({
url: 'WebAPI url',
data: formData,
contentType: false,
processData: false,
// ... Other options like success and etc
})
I want to do the same thing using C# Windows Application, I need to write a Method accepts 2 paramters (FilePath and String) then send the file and the string to WebAPI.
I tried the following code but it returns an error from the service( I am trying to contact with koemei upload service) , although it works fine when I call it from Js :
void SendData(string filepath,string name){
var url = "URL";
HttpContent fileContent = new ByteArrayContent(System.IO.File.ReadAllBytes(filepath));
using (var client = new HttpClient())
{
using (var formData = new MultipartFormDataContent())
{
formData.Add(fileContent, "upload");
formData.Add(new StringContent(name), "name");
//call service
var response = client.PostAsync(url, formData).Result;
if (!response.IsSuccessStatusCode)
{
throw new Exception();
}
else
{
if (response.Content.GetType() != typeof(System.Net.Http.StreamContent))
throw new Exception();
var stream = response.Content.ReadAsStreamAsync();
var content = stream.Result;
var path = @"name.txt";
using (var fileStream = System.IO.File.Create(path))
{
content.CopyTo(fileStream);
}
}
}
}
}
Upvotes: 1
Views: 6691
Reputation: 1101
Here is a sample
private List<ByteArrayContent> GetFileByteArrayContent(HashSet<string> files)
{
List<ByteArrayContent> list = new List<ByteArrayContent>();
foreach (var file in files)
{
var fileContent = new ByteArrayContent(File.ReadAllBytes(file));
fileContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
{
FileName = Path.GetFileName(file)
};
list.Add(fileContent);
}
return list;
}
private List<ByteArrayContent> GetFormDataByteArrayContent(NameValueCollection collection)
{
List<ByteArrayContent> list = new List<ByteArrayContent>();
foreach (var key in collection.AllKeys)
{
var dataContent = new ByteArrayContent(Encoding.UTF8.GetBytes(collection[key]));
dataContent.Headers.ContentDisposition = new ContentDispositionHeaderValue("attachment")
{
Name = key
};
list.Add(dataContent);
}
return list;
}
And here is how to post the data and files
using (HttpClient client = new HttpClient())
{
client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("text/xml"));//set how to get data
using (var content = new MultipartFormDataContent())//post by content type multipart/form-data
{
NameValueCollection dataCollection;//the datas you want to post
HashSet<string> filePaths;//the files you want to post
var formDatas = this.GetFormDataByteArrayContent(dataCollection);//get collection
var files = this.GetFileByteArrayContent(filePaths);//get collection
Action<List<ByteArrayContent>> act = (dataContents) =>
{//declare an action
foreach (var byteArrayContent in dataContents)
{
content.Add(byteArrayContent);
}
};
act(formDatas);//process act
act(files);//process act
try
{
var result = client.PostAsync(this.txtUrl.Text, content).Result;//post your request
}
catch (Exception ex)
{
//error
}
}
}
Upvotes: 1