CODEWITHSUNDEEP
coperators
user3851713
user3851713

Reputation: 17

C operators and evaluation

#include<stdio.h>
int main()
{
int i=3,val;
val=sizeof (f(i))+ +f(i=1)+ +f(i-1);
printf("%d%d",val,i);
getch();
return 0;

}
int f(int num)
{
return num*5;
}

The compiler compiles the program and gives the output 7 1 ..what do the " + +" mean???

Upvotes: 0

Views: 50

Answers (1)

Bathsheba
Bathsheba

Reputation: 234645

First note that sizeof is compile-time evaluable so the first term in val will be sizeof(int): int being the return type of f.

The value of the entire expression that you want to assign to val is undefined since + as a binary and unary operator is not sequenced. In essence you don't know if i = 1 will happen before or after the evaluation of i - 1.

As for your specifics, a + + b is evaluated as a + (+b). +b is simply a unary plus (almost a no-op, but does do some subtle type coercion), the other + is the addition operator taking two arguments.

Upvotes: 2

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