CODEWITHSUNDEEP
pythondictionary
finn
finn

Reputation: 11

.get not working in Python

import os


name = input("Please enter your username ") or "name"
server = input("Please enter a name you wish to call this server ") or "server"
prompt = name + "@" + server


def error(choice):
        print(choice + ": command not found")
        commands()


def clear():
        os.system("cls")
        commands()


def commands():
        while 1 > 0:
                choice = input(prompt)
                {'clear': clear}.get(choice, error(choice))()

commands()

When running this code, no matter what I enter the dictionaries .get function always returns an error. When I enter 'clear' the script should go to that function. Does anyone have an idea why this does not work correctly? Thanks.

Upvotes: 0

Views: 2658

Answers (2)

Open AI - Opting Out
Open AI - Opting Out

Reputation: 24153

You don't want to actually call error(choice).

You can partially apply parameters to a function but leave it to be called later:

>>> def error(choice):
...     print(choice + ': command not found')

>>> from functools import partial
>>> func = partial(error, choice='asdf')
>>> func()
asdf: command not found

So you want:

{'clear': clear}.get(choice, partial(error, choice))()

Upvotes: 1

Daniel Roseman
Daniel Roseman

Reputation: 599788

You'll always see the error, because all arguments to a function must be evaluated before the function is called. So error(choice) will be called to get its result before it is passed as the default value to get().

Instead, leave out the default, and check it explicitly:

result = {'clear': clear}.get(choice)
if result:
    result()
else:
    error(choice)

Upvotes: 3

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