CODEWITHSUNDEEP
ruby-on-railsrubyregex
newbie
newbie

Reputation: 1033

ruby/rails strip out xml code based on regex expression

I receive the following xml in a database field.

<Request type="Final">
    <Field name="Grade">94.5</Field>
    <Field name="EmployeeName">2398;;;Mike5</Field>
    <Field name="Date">051215</Field>
</Request>

Currently, I just receive it and display them as it is:

  def request_xml
    (request.blank? ? "" : request.message)
  end

Now, I want to return the xml by stripping of the EmployeeName value to nil i.e 2398;;;Mike5 from 2398;;;Mike5 based on certain logic

So I am ok with 2 solutions

>  1. if EmployeeName value matches a regex, return null else return the value as it is?
>  - Return <Field name="EmployeeName"></Field>
>  2. if EmployeeName value matches a regex completely strip out the whole EmployeeName XML: <Field
> name="EmployeeName">2398;;;Mike5</Field> from the result

Is either of the above solution possible via ruby/rails code?

Upvotes: 1

Views: 85

Answers (2)

Aleksey Shein
Aleksey Shein

Reputation: 7482

As @asiniy already answered, you can use nokogiri for changing your xml, like this:

UPDATE: you can filter tag contents with the following code:

require 'nokogiri'

xml = Nokogiri::XML('<Request type="Final">
    <Field name="Grade">94.5</Field>
    <Field name="EmployeeName">2398;;;Mike5</Field>
    <Field name="Date">051215</Field>
</Request>')

# remove all Employee elements, containing text 2398
xml.css('Field[name=EmployeeName]').select { |node| node.text =~ /2398/ }.map(&:remove) 

puts xml

will output

<?xml version="1.0"?>
<Request type="Final">
    <Field name="Grade">94.5</Field>

    <Field name="Date">051215</Field>
</Request>

Upvotes: 1

Alex Antonov
Alex Antonov

Reputation: 15156

You can do it through nokogiri gem. Here is official tutorial

require 'nokogiri'

xml = Nokogiri::XML('<Request type="Final">
    <Field name="Grade">94.5</Field>
    <Field name="EmployeeName">2398;;;Mike5</Field>
    <Field name="Date">051215</Field>
</Request>')

if xml.xpath('//EmployeeName')
  do_whatever_you_want

Upvotes: 0

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