CODEWITHSUNDEEP
pythondjangodictionary
NachoMiguel
NachoMiguel

Reputation: 993

Dictionary in Django template - filter usage

i have a view that returns a dict. I searched around SO and found : Django template how to look up a dictionary value with a variable

this is the return statement of my view:

return render(request, 'App/index.html', context={'talks': word_count})

I´m pretty new in django so i think this is why i do not notice the error here. The answer to the mentioned question is this one, create a filter and load it in the template, ok, this is the filter:

from django.template.defaulttags import register

@register.filter
def get_item(dictionary, key):
    return dictionary.get(key)

And here is where i am using it in the wrong way:

<ul>
    {% for talk in talks %}
        <li>{{  talks|get_item:talk.count  }}</li>
    {% endfor %}
</ul>

This is the dictionary i have:

{' - Nacho:': 1211, ' - Pato:': 1950, ' - Nicolas:': 1871, '}

the way i created it is this one:

lista = {}
for line in lines:
            if user in line:
                count += 1
lista[user] = count

simple as that. The error i´m having is this one:

All the elements appear like this:

. None
. None
. None

not knowing exactly how to use the filter is making it hard to fix this Maybe someone with more experience in django can point me in the right direction

Any help will be really appreciated

Upvotes: 1

Views: 918

Answers (1)

Daniel Roseman
Daniel Roseman

Reputation: 599638

Your dictionary items do not have a count attribute.

But I don't know why you think you need this filter at all. You have a simple dictionary, not a complex nested data structure; if you simply want the key (name) and value (count) for each element, just iterate through with items:

{% for name, count in talks.items() %}
    <li>{{ name }} - {{ count }}</li>
{% endfor %}

Upvotes: 3

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