CODEWITHSUNDEEP
phpregex
robjmills
robjmills

Reputation: 18598

Regular expression for end of line phrase

I am grabbing a block of text, and within this block there will be a line containing a phrase that ends with "WITH PASSWORD kEqHqPUd" where kEqHqPUd is a dynamically generated password. What is a simple regular expression for grabbing just the password within this?

I'm using PHP.

Upvotes: 3

Views: 9892

Answers (3)

Tedford
Tedford

Reputation: 2932

Assuming that PHP accepts standard regex patterns, "WITH PASSWORD (.+)+$" should work, where the password will be placed in the first capture group.

Upvotes: 0

Pascal MARTIN
Pascal MARTIN

Reputation: 400952

I am not sure how you define "phrase that ends"... But if you mean "a sentence ends with the password, but could be followed by another sentence", then a solution could be:

$text = <<<TEXT
This is some
text and there is a sentence that ends
with WITH PASSWORD kEqHqPUd. Is that
matched ?
TEXT;

$matches = array();
if (preg_match('/WITH PASSWORD ([\w\d]+)/', $text, $matches)) {
    var_dump($matches[1]);
}

This will only work, though, if the password only contains letters and/or numbers -- but it will work if there is something after "the end of the phrase".


If you meant that the password is the last thing in the whole string, you could use something like this:

$text = <<<TEXT
This is some
text and there is a sentence that ends
with WITH PASSWORD kEqHqPUd
TEXT;

$matches = array();
if (preg_match('/WITH PASSWORD (.+)$/m', $text, $matches)) {
    var_dump($matches[1]);
}

Note that the $ sign means "end of string".

Upvotes: 3

Artefacto
Artefacto

Reputation: 97815

preg_match('/WITH PASSWORD (.*)$/im', $block, $matches);
//result in $matches[1]

The key is the "m" modifier.

Upvotes: 12

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