CODEWITHSUNDEEP
python
Alepale
Alepale

Reputation: 29

Python - Converting contents of a file to int from string

I have a program that saves the scores you get in the program in a seperate file, however, the file saves the score as this:

2 4 6 8 9 8

My problem is that I cannot convert these to integers, so that I then can add them all together to a total sum.

This is as far as I have come:

scores = open("scores.txt", "r")

After that everything I have tried just ends up in different errors.

Anyone got any idea of what to do?

Upvotes: 1

Views: 37489

Answers (7)

jprawiharjo
jprawiharjo

Reputation: 88

There are 2 ways to do this:

The first one is to assume that the other program outputs consistent positive integers with single-space delimiter. You can use this code:

with open('scores.txt', 'r') as f:
    lines = f.read(); 
    q = lines.split(' ')    
    a = sum(map(int, q))

print a

The second solution would be to use regex:

import re
intpattern = '[+-]?\d+'

with open('scores.txt', 'r')as f:
    lines = f.read(); 
    m = re.findall(intpattern, lines)
    a = sum(map(int, m))

print a

Upvotes: 1

Semih Yagcioglu
Semih Yagcioglu

Reputation: 4101

I cannot convert these to integers, so that I then can add them all together to a total sum (which in this case would be 2+4+6+8+9+8 = 37)

You can split a line, cast each string to integer, then sum all the numbers. You might as well store these sums in a list and calculate an average.

Try this:

sums = []
with open("scores.txt", "r") as f:
  for line in f:
    numbers = line.split() # 2 4 6 8 9 8
    s = 0
    for number in numbers:
        try:
            s += int(number)
        except:
            print 'can not cast to integer'
    sums.append(s)
  avg = sum(sums) / float(len(sums))

Upvotes: -1

YOBA
YOBA

Reputation: 2807

Do it as follows:

with open("scores.txt", "r") as f:
    score = f.read() # Read all file in case values are not on a single line
    score_ints = [ int(x) for x in score.split() ] # Convert strings to ints
    print sum(score_ints) # sum all elements of the list

37

Upvotes: 4

Praveen
Praveen

Reputation: 9345

Try:

with open("scores.txt", "r") as f:
    for l in f;
        print(sum([int(a) for a in l.split()]))

Upvotes: 0

p2k
p2k

Reputation: 21

This is how far I have come... "scores = open("scores.txt", "r")" After that everything I have tried just ends up in different errors. Anyone got any idea of what to do?

I would recommend splitting the string by delimiter.

You could do that by going line for line through the file.

for line in scores:
  splitted_line = line.split(' ')
  for values in splitted_line:
    value_as_int = int(values)
    # ... do something with value now

Another recommendation for scanning and handling large data is numpy in my opinion. There are several functions that will import data for you.

I can recommend for myself the genfromtext function. You can define filling values, delimiter and much more there.

Upvotes: 2

Niklas Rosencrantz
Niklas Rosencrantz

Reputation: 26644

You convert to int by writing int(<variable>) e.g.

>>> a='3'
>>> type(a)
<type 'str'>
>>> a=int(a)
>>> type(a)
<type 'int'>

Upvotes: 0

Thargor
Thargor

Reputation: 1872

You have to convert the scores (which are interpreted as Strings) to Integers.

s = "1"
i = int(s)

Upvotes: 1

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