CODEWITHSUNDEEP
rvector
eric_kernfeld
eric_kernfeld

Reputation: 528

Filling list with empty vectors causes its length to change

In the following code, I was expecting something of length 96, but I get a list of length 48. Can you explain this result?

num_empty = 96
empty_vecs = as.list(1:num_empty)
for(i in 1:num_empty){empty_vecs[[i]] = c()}
length(empty_vecs)

[1] 48

Now I'll answer the question that led me to encounter this behavior. The original question was, "How do I make a list of empty vectors in R?" and the answer was "Replace c() with character() in the above code."

Upvotes: 6

Views: 661

Answers (1)

josliber
josliber

Reputation: 44320

Setting list elements equal to c() (aka NULL) removes them, and this loop therefore has the effect of deleting every other element in your list. To see this, consider a smaller example, iteratively printing out the resulting vector:

e <- list(1, 2, 3, 4)
e
# [[1]]
# [1] 1
# 
# [[2]]
# [1] 2
# 
# [[3]]
# [1] 3
# 
# [[4]]
# [1] 4
# 
e[[1]] <- c()
e
# [[1]]
# [1] 2
# 
# [[2]]
# [1] 3
# 
# [[3]]
# [1] 4
# 
e[[2]] <- c()
e
# [[1]]
# [1] 2
# 
# [[2]]
# [1] 4

e[[3]] <- c()
e
# [[1]]
# [1] 2
# 
# [[2]]
# [1] 4

e[[4]] <- c()
e
# [[1]]
# [1] 2
# 
# [[2]]
# [1] 4

Note that if you actually wanted to create a list of 96 NULL values, you might try:

replicate(96, c(), FALSE)

Upvotes: 8

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