CODEWITHSUNDEEP
jqueryforms
Rik89
Rik89

Reputation: 135

return true after jQuery validation wont submit my form

I have a form that I am validating with jQuery, once validation is passed I want to submit the form:

    $(document).ready(function(){
        $('[name="form"]').submit(function(e){
            e.preventDefault();
            var one = $('[name="one"]');
            var two = $('[name="two"]');
            var three = $('[name="three"]');
            var errors = [];

            if(!one.val()){
                errors.push(one);
            }
            if(!two.val()){
                errors.push(two);
            }
            if(!three.val()){
                errors.push(three);
            }

            if(errors.length > 0){
                $.each(errors, function(i, v){
                    $(v).css('border', '1px solid red');
                });
            } else {
                console.log('true');
                $('#bmi-form').submit();
            }
        });
    });

My idea was that the return true at the end would submit the form but it does nothing..

In the console I see the console.log('true');

So how can I submit the form on validation success... I dont want to use any plugins as it is a very small app and there is no need to bloat it.

Regards

Upvotes: 0

Views: 40

Answers (3)

Jai
Jai

Reputation: 74738

As you are using e.preventDefault(); which stops the form to get submitted. Now you can .submit() the form instead of return true;: 

} else {
    console.log('true');
    this.submit(); // return true;
}

or remove the e.preventDefault() and change to this code to submit only when there are no errors: 

if(errors.length > 0){
    $.each(errors, function(i, v){
        $(v).css('border', '1px solid red');
    });
    e.preventDefault(); // put e.preventDefault(); stop to submit incase of errors
} else {
    console.log('true');
    // just remove the return true; from here because if everything is 
}   // fine form will submit. Or you can just remove the else block.

Upvotes: 1

Akki619
Akki619

Reputation: 2432

You need to submit your form...

$("formid").submit();

$(document).ready(function(){
        $('[name="form"]').submit(function(e){
            e.preventDefault();
            var one = $('[name="one"]');
            var two = $('[name="two"]');
            var three = $('[name="three"]');
            var errors = [];

            if(!one.val()){
                errors.push(one);
            }
            if(!two.val()){
                errors.push(two);
            }
            if(!three.val()){
                errors.push(three);
            }

            if(errors.length > 0){
                $.each(errors, function(i, v){
                    $(v).css('border', '1px solid red');
                });
            } else {
                console.log('true');
                $("formid").submit();
            }
        });
    });

Upvotes: 0

Chintan7027
Chintan7027

Reputation: 7605

User $("form").submit(); if your data is in form or of dynamically validation is created then do ajax call; References

API

submit-a-form-using-jquery

Upvotes: 0

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