Reputation: 1773
I have strings in two datasets and i would like to do a partial match. Here is the code that I have written
df1 <- data.frame(A=c(.87,.11,.44,.45), B=c("I have a beard", "I slept for two hours", "I have had two courses","this is not true"))
df2 <- data.frame(X=c(127,10,433,344,890,4),Y=c("have","beard","syllabus","true","three","maths"))
I want to do a pmatch and I am expecting output as follows
A B X Y
.87 I have a beard 127 have
.11 I slept for two hours NA NA
.44 I have had two courses 127 have
.45 this is not true 344 true
I would like to a partial match with a left join on df1. I want to get the higher of the two matches(for example in "I have a beard" string "have" match has 127 and "beard" has 10 and i want to get the higher match. Any suggestions?
Upvotes: 1
Views: 778
Reputation: 16121
This dplyr
method doesn't need a join
(which is reasonable as you don't have a common column to join on). It combines the 2 datasets and finds the matches. As long as you don't have thousands of rows it will work fast enough. Of course you can make the script smaller, but you can run this step by step to see how it works.
df1<- data.frame(A=c(.87,.11,.44,.45), B=c("I have a beard", "I slept for two hours", "I have had two courses","this is not true"))
df2<- data.frame(X=c(127,10,433,344,890,4),Y=c("have","beard","syllabus","true","three","maths"))
library(dplyr)
df1 %>%
rowwise() %>%
do(data.frame(.,df2)) %>% # combine datasets
do(data.frame(.,flag = grepl(.$Y,.$B))) %>% # for each row check if there's a match and name it flag
ungroup %>%
group_by(A,B) %>% # for each A and B
mutate(N=sum(flag)) %>% # count how many matches you have
filter(flag==TRUE | N == 0) %>% # keep only A,B where you have some matches or no match at all
top_n(1,X) %>% # pick one row based on max value of X
ungroup %>%
mutate(Y = ifelse(flag==FALSE,NA,as.character(Y)), # if there's no match replace Y with NA
X = ifelse(flag==FALSE,NA,X)) %>% # if there's no match replace X with NA
select(-c(flag,N))
# A B X Y
# 1 0.87 I have a beard 127 have
# 2 0.11 I slept for two hours NA NA
# 3 0.44 I have had two courses 127 have
# 4 0.45 this is not true 344 true
Try to experiment and change various column values to see how it works. You might be able to spot any bugs in advance.
Upvotes: 1
Reputation: 21621
Another option:
library(dplyr)
df1 %>%
mutate(X = sapply(strsplit(as.character(B), ' '),
function(x) with(df2, max(X[Y %in% x])))) %>%
left_join(., df2)
Which gives:
#Joining by: "X"
# A B X Y
#1 0.87 I have a beard 127 have
#2 0.11 I slept for two hours -Inf <NA>
#3 0.44 I have had two courses 127 have
#4 0.45 this is not true 344 true
Upvotes: 1