regular expression with Python required

Question

I have a string path as:

"Z:\results\cfg3\clear1"

I need a python string method to capture whatever Number comes after cfg but before the \ . Note that string before \cfg\ and after it could change, so I cannot use string length. So, basically, with following 2 versions

"Z:\results\cfg3\clear1"

"Z:\results1\enhanced\cfg1\clear2\final"

the script should return cfg3 and cfg1 as the answers.

Any ideas using regular expression?
sedy

Answer 1

>>> import re
>>> re.findall(r'.*(cfg\d+).*', "Z:\results\cfg3\clear1")
['cfg3']