CODEWITHSUNDEEP
pythonstringcount
python_newbie
python_newbie

Reputation: 123

counting the number of vowels in a word in a string

I am a beginner, and I am trying to find out the number of vowels in each word in a string. So for instance, if I had "Hello there WORLD", I want to get an output of [2, 2, 1].

Oh, and I am using Python.

I have this so far

[S.count(x) in (S.split()) if x is 'AEIOUaeiou']

where S="Hello there WORLD"

but it keeps saying error. Any hints?

Upvotes: 1

Views: 168

Answers (2)

Veky
Veky

Reputation: 2755

Obviously, S in S.count and S in S.split cannot be the same S. I suggest using more semantic names.

>>> phrase = 'Hello there WORLD'
>>> [sum(letter.casefold() in 'aeiouy' for letter in word) for word in phrase.split()]
[2, 2, 1]

Upvotes: 0

Open AI - Opting Out
Open AI - Opting Out

Reputation: 24153

x is 'AEIOUaeiou'

This tests whether x is precisely the same object as 'AEIOUaeiou'. This is almost never what you want when you compare objects. e.g. the following could be False:

>>> a = 'Nikki'
>>> b = 'Nikki'
>>> a is b
False

Although, it may be True as sometimes Python will optimise identical strings to actually use the same object.

>>> a == b
True

This will always be True as the values are compared rather than the identity of the objects.

What you probably want is:

x in 'AEIOUaeiou'

Upvotes: 1

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