CODEWITHSUNDEEP
pythondictionary-comprehension
wa7d
wa7d

Reputation: 229

Using dictionary comprehension to find vowels in string?

Assuming S = "Tea Lemon CoffEE cAke".lower()

    { x:y.count('aeoiu') for x in S.split() for y in 'aeoiu' if y in 'aeoiu' }

the output of this is:

    {'cake': 0, 'tea': 0, 'lemon': 0, 'coffee': 0}

Why is it giving me 0s and not the number of vowels in each word? I'm new to python and I would appreciate some hints. Totally not looking for straight answers.

Upvotes: 0

Views: 958

Answers (1)

Blorgbeard
Blorgbeard

Reputation: 103525

I think you want to do this:

{ x: sum(x.count(y) for y in 'aeoiu') for x in S.split() }

Which outputs:

{'coffee': 3, 'cake': 2, 'lemon': 2, 'tea': 2}

Your code was counting the number of times the string 'aeoiu' occurs in y, which is always zero. Also note that for y in 'aeoiu' if y in 'aeoiu' is redundant, you don't need the if.

Upvotes: 5

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