Reputation: 2549
The array given has duplicate elements, So basically, I want to find the index
of the last occurrence of the element I've searched.
$arr = array(2, 3, 4, 4, 5, 6, 4, 8);
$x = 4; // number to search
$low = 0;
$high = count($arr)-1;
// I want this function to return 6 which is the index of the last occurrence of 4, but instead I'm getting -1 .
function binary_search_last_occ($arr, $x, $low, $high)
{
while ($low <=$high)
{
$mid = floor(($low+$high)/2);
$result = -1;
if ($arr[$mid] == $x)
{
// we want to find last occurrence, so go for
// elements on the right side of the mid
$result = $mid;
$low = $mid+1;
}
else if($arr[$mid] > $x)
{
$high = $mid-1;
}
else
$low = $mid+1;
}
return $result;
}
echo binary_search_last_occ($arr, $x, $low, $high); // outputs -1 ?
I'm not sure, why I'm getting -1. Any suggestions?
Upvotes: 3
Views: 1191
Reputation: 99
First of all for binary search your array must be sorted, if your array is not sorted you can use simple method like
function binary_search_last_occ($arr, $x, $low, $high)
{
$last_occ = -1;
while ($low <=$high)
{
if($arr[$low] == $x)
$last_occ = $low;
$low++;
}
return $last_occ ;
}
Upvotes: 2
Reputation: 9675
And also define $result
above while() to avoid overriding every time with -1
. Hence you get the result as -1.
$result = -1;
while ($low <=$high)
{
$mid = floor(($low+$high)/2);
if ($arr[$mid] == $x)
{
// we want to find last occurrence, so go for
// elements on the right side of the mid
$result = $mid;
$low = $mid+1;
}
else if($arr[$mid] > $x)
{
$high = $mid-1;
}
else
$low = $mid+1;
}
return $result;
Upvotes: 1
Reputation: 21422
I didn't seen your loop but I think this'll really simple to use to gain such functionality
$arr = array(2, 3, 4, 4, 5, 6, 4, 8);
$result = [];
foreach($arr as $key => $val){
$result[$val][] = $key;
}
echo end($result[4]);//6
Or you can simply use the asort
function along with array_search
like as
$arr = array(2, 3, 4, 4, 5, 6, 4, 8);
asort($arr);
echo array_search(4,$arr);//6
Upvotes: 2