Reputation: 384
I am showing option with chosen plugin and latter add option to it.
I am trying below
<select id='one'>
<option>a</option>
<option>b</option>
</select>
and calling chosen plugin
$('#one').chosen();
it working fine now i am remove chosen part and adding new option to select box
$('#one').append(' <option>g</option>');
$('#one').addClass('abc').attr('id', '');
$('#one_chosen').remove();
$('.abc').attr('id', 'myid');
$('#myid').chosen();
as you can see that i have added id by class and calling chosen() on it but this time its not working. And i can not keep id one in select box if there is no chosen
Upvotes: 0
Views: 606
Reputation: 8122
i am not sure i understand your question. But you can refresh chosen
with .trigger("chosen:updated");
i.e you can do something like
$('.select-chosen').chosen();
$('#one').addClass('abc').attr('id', '');
$('.abc').attr('id', 'myid');
$('.select-chosen').trigger("chosen:updated");
Ideally, if you want to fully change the select chosen
, it is better to just hide and show new select chosen
. In case, if you want to add
or remove
option from select and want to gain fully functionality of chosen you can do it easily with
// add custom option
$(".select-chosen").append('<option>Custom Option</option>');
// remove existing option
$(".select-chosen option[value='a']").remove();
Refer : http://jsfiddle.net/qubkhtsc/5/
Upvotes: 0
Reputation: 24276
You must clone the element in order to make it work:
$('#one').chosen();
$('#one').find('option:first').remove();
$myid = $('#one').clone().attr('id', 'myid').insertBefore('#one');
$("#one, #one_chosen").remove();
$myid.show().chosen();
Upvotes: 1