CODEWITHSUNDEEP
swiftdictionaryswift2
Andrius Steponavičius
Andrius Steponavičius

Reputation: 8184

extension of Dictionary where <String, AnyObject>

I am trying to create a dictionary extension where Dictionary is of the type <String, AnyObject>.

Was looking in many places and trying different approaches, but none of them seemed to work. This was one of them:

extension Dictionary where <String, AnyObject>{
    var jsonString:String {
        return ""
    }
}

Another method that didn't actually work for some reason:

extension Dictionary where Key:Hashable, Value:AnyObject {

    var jsonString:String {

        do {
           let stringData = try NSJSONSerialization.dataWithJSONObject(self, options: NSJSONWritingOptions.PrettyPrinted)
            if let string = String(data: stringData, encoding: NSUTF8StringEncoding){
                return string
            }
        }catch _ {

        }
        return ""
    }
}

Got: Argument type 'Dictionary' does not conform to expected type of 'AnyObject'

Upvotes: 54

Views: 41459

Answers (7)

Dhaval H. Nena
Dhaval H. Nena

Reputation: 4130

Anyone using [String:Any] instead of Dictionary can use below extension

extension Dictionary where Key == String, Value == Any {

    mutating func append(anotherDict:[String:Any]) {
        for (key, value) in anotherDict {
            self.updateValue(value, forKey: key)
        }
    }
}

Upvotes: 6

Jonauz
Jonauz

Reputation: 4133

Update for Swift 3
Here is my example using ExpressibleByStringLiteral for Key and Any for Value.

extension Dictionary where Key: StringLiteralConvertible, Value: Any {
    var jsonString: String? {
        if let dict = (self as AnyObject) as? Dictionary<String, AnyObject> {
            do {
                let data = try JSONSerialization.data(withJSONObject: dict, options: JSONSerialization.WritingOptions(rawValue: UInt.allZeros))
                if let string = String(data: data, encoding: String.Encoding.utf8) {
                    return string
                }
            } catch {
                print(error)
            }
        }
        return nil
    }
}

and then I use it like this:

let dict: Dictionary<String, AnyObject> = [...]
let jsonString = dict.jsonString

You can convert self to AnyObject or NSObject, both works, then you do unwrap as Dictionary or any other specific type.

Upvotes: 8

Logan
Logan

Reputation: 53112

>=3.1

From 3.1, we can do concrete extensions, ie:

extension Dictionary where Key == String {}

<3.1

We can not conform concrete types w/ concrete generics, ie: 

extension Dictionary where Key == String

However, because Dictionary conforms to sequence and we can conform protocol types w/ concrete generics, we could do:

extension Sequence where Iterator.Element == (key: String, value: AnyObject) {
    func doStuff() {...

Otherwise, we can constrain our key to a protocol that string conforms to like this:

extension Dictionary where Key: StringLiteralConvertible, Value: AnyObject {
    var jsonString: String {
        return ""
    }
}

As per your updated answer. Json serialization needs an object, Swift Dictionaries are structs. You need to convert to an NSDictionary You must specify Key to conform to NSObject to properly convert to an NSDictionary.

Small note: Dictionaries already type constrain Key to be Hashable, so your original constraint wasn't adding anything.

extension Dictionary where Key: NSObject, Value:AnyObject {

    var jsonString:String {

        do {
            let stringData = try NSJSONSerialization.dataWithJSONObject(self as NSDictionary, options: NSJSONWritingOptions.PrettyPrinted)
            if let string = String(data: stringData, encoding: NSUTF8StringEncoding){
                return string
            }
        }catch _ {

        }
        return ""
    }
}

Note, that the dictionaries must conform to this type to access the extension.

let dict = ["k" : "v"]

Will become type [String : String], so you must be explicit in declaring:

let dict: [NSObject : AnyObject] = ["k" : "v"]

Upvotes: 119

Aidan Malone
Aidan Malone

Reputation: 418

Swift 3 Approach

extension Dictionary where Key: ExpressibleByStringLiteral, Value: AnyObject

As StringLiteralConvertible is now deprecated and replaced by ExpressibleByStringLiteral

Upvotes: 9

Drew C
Drew C

Reputation: 6458

I was not able to make any of the offered solutions work in Swift 3, but by taking advantage of bridging between Dictionary and NSDictionary I could make this work:

extension NSDictionary {

    var jsonString:String {

        do {
            let stringData = try JSONSerialization.data(withJSONObject: self, options: .prettyPrinted)
            if let string = String(data: stringData, encoding: .utf8) {
                return string
            }
        }catch _ {

        }
        return ""
    }
}

Upvotes: 2

Jason Henderson
Jason Henderson

Reputation: 51

Adding to the answer provided by @Logan, for those looking to add custom properties to the string-subscripted Dictionary, that is possible as well (was looking to do this when I came across this SO question):

extension Dictionary where Key: StringLiteralConvertible {

    var somePropertyThatIsAColor:UIColor? {
        get {
            return self["someKey"] as? UIColor
        }
        set {
            // Have to cast as optional Value
            self["someKey"] = (newValue as? Value)
    }

}

Upvotes: 5

Andrei Popa
Andrei Popa

Reputation: 169

So, Dictionary is:

public struct Dictionary<Key : Hashable, Value> : CollectionType, DictionaryLiteralConvertible {..}

How about a protocol extension? :D

extension CollectionType where Self: DictionaryLiteralConvertible, Self.Key == String, Self.Value == AnyObject, Generator.Element == (Self.Key, Self.Value) {
...
}

Upvotes: 3

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