CODEWITHSUNDEEP
iosobjective-cswift
Tomaž Polič
Tomaž Polič

Reputation: 31

Calling Objective-c function in swift

Im trying to implement CometChat in my swift application. I managed to import the Objective-c framework successfully via a bridging header. But now I'm stuck trying to call Objective-C methods from swift.

This is the method from the interface i want to call:

- (void)loginWithURL:(NSString *)siteURL
            username:(NSString *)username
            password:(NSString *)password
             success:(void(^)(NSDictionary *response))success
             failure:(void(^)(NSError *error))failure;

And this is how the method is called from Objective-C:

 [cometChat loginWithURL:@"localhost/cometchat/" username:usernameTextField.text password:passwordTextField.text success:^(NSDictionary *response) {

                    NSLog(@"SDK log : Username/Password Login Success %@",response);

                    [self handleLogin];

                } failure:^(NSError *error) {

                    NSLog(@"SDK log : Username/Password Login Error%@",error);

                    [self handleLoginError:@[@0,error]];

                }];

So far i have this:

 cometChat.loginWithURL("localhost/cometchat/", username: EmailField.text, password: PasswordField.text){
            (success: [NSDictionary], failure:NSError) in {

            println("did i make it here?")

            }

    }

The problem is, it says that there is missing argument "success", but its a mystery to me how it can be an argument, when it clearly returns the response. I want to know how to put together this method call. I also used the objectivec2swift converter, but it wasn't any help. Also, i have no clue what the @ means before the @[@0,error]

I know its a beginners question, but i already wasted a whole day on this, since i couldn't find any tutorials on how to call such "complex" Obj-C methods from swift.

Upvotes: 1

Views: 382

Answers (3)

gnasher729
gnasher729

Reputation: 52530

When you call a function, and the last parameter is a block / closure, then you can write the last parameter after the function call in { }. That applies to the last block only.

Anyway, you are trying to pass a closure with two parameters success and failure. You need to pass two closures, one as the success parameter of your function, with a parameter response, and one either as the failure parameter of your function, or following the function, with a parameter error.

Upvotes: 1

SDS
SDS

Reputation: 211

Try this :-

cometChat.loginWithURL("localhost/cometchat/", username: "abc", password: "123", success: { (response) -> Void in

        print("SDK log : Username/Password Login Success \(response)")


        }) { ( error) -> Void in

            print("SDK log : Username/Password Login Error \(error)")
    }

Upvotes: 4

Michael
Michael

Reputation: 6517

When you look at the Objective-C signature, you see that the method takes two closures: success is a void function that takes a dictionary, and failure is a void function that takes an error.

In your Swift code you have only one closure: a void function that takes a dictionary and an error.

You either need to change the Objective-C method to take just one closure, or change the Swift code to provide two closures.

Upvotes: 1

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