Claudiu
Claudiu

Reputation: 229491

Is there a way to use SFINAE to detect whether a non-templated non-member function is not declared?

I'm trying to answer this question using SFINAE and decltype. To summarize, the poster wants a function which acts differently depending on whether another function is declared in the compilation unit (be it declared earlier or later than the function in question).

I tried the following:

auto some_function_2_impl(int) -> decltype(some_function_1(), void()) {
    cout << "Using some_function_1" << endl;
    some_function_1();
}

void some_function_2_impl(long) {
    cout << "Not using some_function_1" << endl;
}

void some_function_2() {
    return some_function_2_impl(0);
}   

However, I get this error message:

main.cpp:4:60: error: 'some_function_1' was not declared in this scope
 auto some_function_2_impl(int) -> decltype(some_function_1(), void()) {

That is the whole point, I thought - I don't want that overload of some_function_2_impl to be defined, because some_function_1 does not exist.

I thought maybe SFINAE requires templates to work, so I tried the following (this may help to indicate that I don't fully know what I'm doing here):

template <int foo>
auto some_function_2_impl(int) -> decltype(some_function_1(), void()) {
    cout << "Using some_function_1" << endl;
    some_function_1();
}

template <int foo>
void some_function_2_impl(long) {
    cout << "Not using some_function_1" << endl;
}

However, now I get the following error:

main.cpp:5:60: error: there are no arguments to 'some_function_1' that 
depend on a template parameter, so a declaration of 'some_function_1'
must be available [-fpermissive]
 auto some_function_2_impl(int) -> decltype(some_function_1(), void()) {

What am I doing wrong?

Upvotes: 4

Views: 205

Answers (1)

Yakk - Adam Nevraumont
Yakk - Adam Nevraumont

Reputation: 275760

Lookup of functions is done immediately, even in template types, except when there is a possible ADL lookup depending on a template parameter type.

Then that ADL lookup is done after types are substituted in. If it fails, the result is a substitution failure.

As your function call is not dependent on the argument types, this technique will not work.

We can still do something modestly fun:

template<class T, class...Ts>
struct first_two_match : std::false_type{};
template<class T, class...Ts>
struct first_two_match<T,T,Ts...>:std::true_type{}; // for standard compliance: If the only Ts... that match Ts... is nothing, program ill-formed.
struct secret_type_tag {};
template<class...Ts,
  std::enable_if_t<
    (sizeof...(Ts)==0) || first_two_match<secret_tag_type,Ts...>{}
  >* =nullptr
>
secret_type_tag some_function_1(Ts&&...);

template<bool b>
using bool_t=std::integral_constant<bool, b>;
static const auto some_function_defined = bool_t<
  !std::is_same<secret_tag_type, decltype( some_function_1() )>{}
>;

Now some_function_defined is std::true_type iff there is an overload of some_function_1 that is preferred over my some_function_1(Ts&&...). As some_function_1(Ts&&...) is very low priority, any "real" overload (that isn't also a forwarding reference glomer and takes 0 arguments) will be preferred.

Making such a low priority overload that is never selected if there is a real overload is tricky in more complex situations.

This still just detects if some_function_1 is defined at the point where some_function_defined is created. Humbug.

Upvotes: 4

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