CODEWITHSUNDEEP
pythonopencvnumpy
yodish
yodish

Reputation: 763

OpenCV - altering the filter2D function

In order to convolve a kernel with an image, I am using: 

 output = cv2.filter2D(image,-1,kernel)

This is returning the convolution image that i'm looking for, however I need to trim the height and width both by 2. For example, it is currently returning output.shape = (157, 298) and I need it to return (155,296) . I cannot alter the image or the kernel.

Is there a way to perhaps begin at image[1,1] (instead of [0,0]) and end at [-1,-1] in order to trim 2 from both axes?

Upvotes: 1

Views: 664

Answers (1)

askewchan
askewchan

Reputation: 46530

You don't have to "alter" the image, you can just slice it. Either before or after, which may have subtly different effects at the edge:

output = cv2.filter2D(image, -1, kernel)[1:-1, 1:-1]

or

output = cv2.filter2D(image[1:-1, 1:-1], -1, kernel)

Upvotes: 2

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