CODEWITHSUNDEEP
javajavafx-2
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Reputation: 5532

Loading an Image in JavaFX

I am trying to load an image in JavaFX using it's Image class.

Here is my code:

Image image = new Image(file.getAbsolutePath());

file is just a file loading the image.

I get the following error:

java.lang.IllegalArgumentException: Invalid URL or resource not found

Here's the full code:

FileChooser fileChooser = new FileChooser();
fileChooser.getExtensionFilters().addAll(
        new FileChooser.ExtensionFilter("JPG","*.jpg"),
        new FileChooser.ExtensionFilter("JPEG","*.jpeg")
);
fileChooser.setTitle("Choose file...");
fileChooser.setInitialDirectory(
        new File(System.getProperty("user.home"))
);
File file = fileChooser.showOpenDialog(stageOfEvent);

if(file != null) {
    Image image = new Image(file.getAbsolutePath());
    imageView.setImage(image);
}

Upvotes: 1

Views: 1064

Answers (1)

Tunaki
Tunaki

Reputation: 137074

In order to construct an Image with a file located in the filesystem, you need to use the file: protocol, like this:

Image image = new Image("file:" + file.getAbsolutePath());

Not specifying it tells JavaFX to look for the image in the classpath, rather than in the filesystem.

Quoting the Image Javadoc:

// The image is located in my.res package of the classpath
Image image2 = new Image("my/res/flower.png", 100, 150, false, false);

// The image is located in the current working directory
Image image4 = new Image("file:flower.png", 0, 100, false, false);

This construct comes from the URL syntax of Java.

As noted by @mipa in the comments, you can also use:

Image image = new Image(file.toURI().toURL().toExternalForm());

Upvotes: 2

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