CODEWITHSUNDEEP
javajava.util.scanner
Ninja
Ninja

Reputation: 67

Separating the digits of a three-digit integer

For my APCS class, my assignment was to take a three-digit number inputed by the user and to print each digit in order on separate lines. My code works fine:

import java.util.Scanner;
public class threeDigits
{
    public static void main (String [] args ){
        System.out.println("Give me a three digit integer and I will print out each individual digit");
        Scanner input = new Scanner(System.in);
        int number = input.nextInt();
        int digit1 = number / 100;
        int digit2 = (number % 100)/10;
        int digit3 = number % 10;
        System.out.println(digit1);
        System.out.println(digit2);
        System.out.println(digit3);
    }
}

What I would like to know is if there is a better, more simple way to get the same result or if this is the best way to do it. Even if this is the most quick-and-dirty way to get the result, I would love to see alternate ways of doing the same thing, not to hand in for a grade but just as a learning experience.

Upvotes: 3

Views: 12197

Answers (5)

Gigi C. Valdez
Gigi C. Valdez

Reputation: 1

import java.util.Scanner;

class Main {
    public static void main(String args[]) {

        Scanner input = new Scanner(System.in);

        int n = input.nextInt();
        int iter = n, sum = 0;

        while(iter > 0) {
            sum = sum + iter;
            iter--;
        }

        System.out.println("The sum from 1 to " + n + " is " + sum + ".");
    }
}

Upvotes: 0

user3761001
user3761001

Reputation: 128

A nice solution is by using a stack.

public static void main(String[] args) {
    System.out.println("Enter number: ");
    Scanner input = new Scanner(System.in);
    int num = input.nextInt();
    input.close();

    if(num<0)
        num*=-1;

    Stack<Integer> stack = new Stack<Integer>();
    while (num != 0)
    {
        stack.push(num%10);
        num/=10;
    }
    int count=1;
    while(!stack.isEmpty())
    {
        System.out.println("digit" + count + ": " + stack.pop());
        count++;
    }
}

Don't forget to import it.

import java.util.Stack;

Upvotes: 0

ashiquzzaman33
ashiquzzaman33

Reputation: 5741

Alternate solution:

First input a integer and convert it to String then loop through the String.

     public static void main (String [] args ) {
        System.out.println("Give me a three digit integer and I will print out each individual digit");
        Scanner input = new Scanner(System.in);
        int number = input.nextInt();
        String str = Integer.toString(number);
        for(int i=0; i<str.length(); i++){
            System.out.println(str.charAt(i));
        }
    }

Upvotes: 2

folkol
folkol

Reputation: 4883

One way would be to read the number as a String instead, and loop through the chars:

import java.util.Scanner;
public class ThreeDigits
{
    public static void main (String [] args ){
        System.out.println("Give me a three digit integer and I will print out each individual digit");
        Scanner input = new Scanner(System.in);
        String number = input.next();

        for(char c : number.toCharArray())
            System.out.println(c);
    }
}

Upvotes: 0

Tunaki
Tunaki

Reputation: 137114

Another solution, if Java 8 and built-in methods are allowed, is to iterate over the characters of the number as a String and print them using forEach.

int number = 12345;
String.valueOf(number).chars().map(Character::getNumericValue).forEach(System.out::println);
// or String.valueOf(number).chars().forEach(c -> System.out.println((char) c));

Upvotes: 1

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