Reputation: 1746
I'm facing a very minor issue, but somehow can't resolve it.
When I'm importing a csv file that has date, the date is coming in "%Y-%m-%d" format. But I want it to be in "%d-%m-%Y" format. I tried "as.Date" to transform it. But it's not working.
The data structure look like this after importing:
Date Share_Val
21/01/2015 20
22/01/2015 19
23/01/2015 21
24/01/2015 23
25/01/2015 26
But when I'm importing the file by read.csv, the data look like the following:
Date Share_Val
01/21/2015 20
01/22/2015 19
01/23/2015 21
01/24/2015 23
01/25/2015 26
I tried lubridate. But it didn't help. Sam's result comes exactly the way I wanted. But when I'm trying the following, it's not coming
data$date<-format(as.Date(data$date,"%m/%d/%Y"))
Can anybody please give me any suggestions?
Upvotes: 0
Views: 282
Reputation: 59355
Too long for a comment.
I think you may be misunderstanding how Dates work in R. A variable (or column) of class Date
is stored internally as the number of days since 1970-01-01. When you print a Date
variable, it is displayed using the %Y-%m-%d
format. The as.Date(...)
function converts character to Date. The format=...
argument controls how the character string is interpreted, not how the result is displayed, as in:
as.Date("02/05/2015", format="%m/%d/%Y")
# [1] "2015-02-05"
as.Date("02/05/2015", format="%d/%m/%Y")
# [1] "2015-05-02"
So in the first case the string is interpreted as 05 Feb, in the second 02 May. Note that in both cases the result is displayed (printed) in %Y-%m-%d
format.
Upvotes: 1
Reputation: 6203
See if this helps. Note the stringsAsFactors
. If your Date
field is a factor, you will need data$Date <- as.character(data$Date)
first
data <- data.frame(Date = c("21/01/2015", "22/01/2015", "23/01/2015",
"24/01/2015", "25/01/2015"), Share_Val=c(20, 19, 21, 23, 26),
stringsAsFactors=F)
format(as.Date(data$Date, "%d/%m/%Y"), "%d-%m-%Y")
[1] "21-01-2015" "22-01-2015" "23-01-2015" "24-01-2015" "25-01-2015"
Upvotes: 2