Reputation: 11
I have to enter random names and weights and finish the loop when I hit enter instead of the name. However the way I used to detect the enter does not serve to take the name so getting two variables. The question is how to put the enter of the test and name using the same variable
#include <stdio.h>
#include <string.h>
#include <ctype.h>
int main() {
int c, weight[1000], i = 0;
char name[1000];
puts ("Enter the person's name or only enter to end the program");
if ((c = getchar() == '\n')) {
} else {
while (c != '\n') {
printf("Enter the name");
scanf("%s", &nome[i]);
i++;
printf("Enter the \n");
scanf("%i", &weight[i]);
}
}
return 0;
}
Upvotes: 0
Views: 107
Reputation: 34585
Here is a simple example
#include <stdio.h>
#include <string.h>
int main(void)
{
char name[1000] = {0}; // initialise
puts ("Enter the person's name or only enter to end the program");
if (fgets(name, sizeof(name), stdin) != NULL) {
name [ strcspn(name, "\r\n") ] = 0; // remove trailing newline etc
if (strlen(name)) {
printf("The name entered was: %s\n", name);
}
else {
printf("You did not enter a name\n");
}
}
return 0;
}
Upvotes: 2
Reputation: 13171
First off, names
is an array of characters and you're treating it like an array of strings. Secondly, loops that need to exit based on input are most clearly expressed with break
:
char *names[1000];
int count = 0;
while (1) {
char *r, buf[1000];
int len;
char *r = fgets(buf, 1000, stdin);
if (NULL == r) break; // EOF
if ((len = strlen(buf)) < 2) break; // NL only
r = malloc(len + 1);
if (NULL == r) break;
strcpy(r, buf);
names[count] = r;
count += 1;
...
}
...
Upvotes: 1