Reputation: 11
I want to order some student details according to their distance to school. But within (80-90)km order first. remaining students will be displayed then. (select student_name, distance from Students ...........) ex :
Can somebody help me on this.
Upvotes: 1
Views: 70
Reputation: 94914
In order to get the 80-90 km distances first, use a CASE construct:
ORDER BY
CASE WHEN distance BETWEEN 80 AND 90 THEN 0 ELSE 1 END,
distance;
This will get you this order:
Geetha 82.5 km Nimal 86.1 km kamal 88.2 km Rani 23.1 km Perera 92.3 km Shashi 102.4 km
First 80-90 km beginning with 82.5 ending with 88.2, then the other distances beginning with 23.1 ending with 102.4.
Upvotes: 3
Reputation: 109557
SELECT ..., ROUND(distance / 10, 0) AS lakhm, ...
...
ORDER by lakhm
This assumes that your SQL version has a ROUND working on expressions. The formal standard requires a column name only I believe. I doubt it works, but ROUND(distance, -1)
should have an equivalent effect.
Upvotes: 0